Answer:
CH
Explanation:
92.26% = 92.26 g
7.74% = 7.74 g
carbon is 92.26 x 1 mole/12.011 = 7.68
hydrogen is 7.74 x 1 mole/1.008 = 7.68
carbon 7.68 ÷ hydrogen 7.68 = 1
so 1 is your subscript for both carbon and hydrogen
Answer:
12.044 x 10^23 atoms Na
Explanation:
1 mol Na has 6.022 x 10^23 atoms of Na
2 moles Na have 2 x NA = 2 x 6.022 x10^23 atoms Na
Well ask yourself why don't we count it in moles and you should get your answer.
The mass of ethanol present in the vapor is 8.8×10⁻²g. when liquid and vapor ethanol at equilibrium.
The volume of the bottle = 4.7 L
Mass of ethanol = 0.33 g
Temperature (T1) = -11 oC = 273-11 = 262 K
P1 = 6.65 torr
Now we will calculate the mole by applying the ideal gas equation:-
PV = nRT
Or, n = PV/RT
Where P is the pressure
T is the temperature
R is the gas constant = 0.0821 L atm mol-1K-1
V is the volume
Substituting the values of P, V, T, and R the mole of ethanol is calculated as:-
= 0.001913 mol C2H6
Conversion of the mole to gm
Molar mass of ethanol (M) = 46.07 g/mol
Mass of C2H6O =0.001913 mol C2H6O 46.07 g/mol = 0.088 = 8.8×10⁻²g.
Hence, the mass of ethanol present in the vapor is found to be 8.8×10⁻²g.
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Answer:
0.6522 mol/L.
Explanation:
<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>
<em />
M = (no. of moles of solute)/(V of the solution (L)).
<em>∴ M = (no. of moles of solute)/(V of the solution (L)) </em>= (1.5 mol)/(2.3 L) = <em>0.6522 mol/L.</em>