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scoray [572]
2 years ago
5

Which of the following best describes subduction?

Chemistry
1 answer:
siniylev [52]2 years ago
5 0

Answer:

A more dense plate going underneath a less dense plate.

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Find the empirical and the molecular formula of acetylene gas composed of 92.26 percent carbon and 7.74 percent hydrogen
Hitman42 [59]

Answer:

CH

Explanation:

92.26% = 92.26 g

7.74% = 7.74 g

carbon is 92.26 x 1 mole/12.011 = 7.68

hydrogen is 7.74 x 1 mole/1.008 = 7.68

carbon 7.68 ÷ hydrogen 7.68 = 1

so 1 is your subscript for both carbon and hydrogen

6 0
3 years ago
2 moles Na = ______ atoms Na. I need help to figure out the number of atoms in Avogadro's number
Reil [10]

Answer:

12.044 x 10^23 atoms Na

Explanation:

1 mol Na has 6.022 x 10^23 atoms of Na

2 moles Na have 2 x NA = 2 x 6.022 x10^23 atoms Na

4 0
3 years ago
Read 2 more answers
Why are familiar objects such as pens and paper clips not commonly counted in moles?
Anton [14]
Well ask yourself why don't we count it in moles and you should get your answer.
6 0
3 years ago
A 4.7-L sealed bottle containing 0.33 g of liquid ethanol,C₂H₆O, is placed in a refrigerator and reaches equilibrium with its va
Mama L [17]

The mass of ethanol present in the vapor is 8.8×10⁻²g. when liquid and vapor ethanol at equilibrium.

The volume of the bottle = 4.7 L

Mass of ethanol = 0.33 g

Temperature (T1) = -11 oC = 273-11 = 262 K

P1 = 6.65 torr

Now we will calculate the mole by applying the ideal gas equation:-

PV = nRT

Or, n = PV/RT

Where P is the pressure

 T is the temperature

 R is the gas constant = 0.0821 L atm mol-1K-1

 V is the volume

Substituting the values of P, V, T, and R the mole of ethanol is calculated as:-

  = 0.001913 mol C2H6

Conversion of the mole to gm

Molar mass of ethanol (M) = 46.07 g/mol

Mass of C2H6O =0.001913 mol C2H6O 46.07 g/mol = 0.088 =  8.8×10⁻²g.

Hence, the mass of ethanol present in the vapor is found to be  8.8×10⁻²g.

Learn more about mole here:-brainly.com/question/15374113

#SPJ4

8 0
1 year ago
Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution
frosja888 [35]

Answer:

0.6522 mol/L.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

M = (no. of moles of solute)/(V of the solution (L)).

<em>∴ M = (no. of moles of solute)/(V of the solution (L)) </em>= (1.5 mol)/(2.3 L) = <em>0.6522 mol/L.</em>

7 0
3 years ago
Read 2 more answers
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