Formula
Area = L*w
Hint : To find the area of a rectangle , multiply the length times the width
I hope that's help !
Answer:
yep thats correct
Step-by-step explanation:
Answer:
this is your answer........
Answer:
Step-by-step explanation:
Hello!
The sample shows the scores for the combined three-part SAT.
Raw data in first attachment.
a.
To arrange the data in a frequency table using class intervals you have to determine the number of intervals you want to use and calculate their width. In this case, the width is given and so is the lower limit of the first interval, you calculate the successive limits by adding the width. The lower limit of the next interval will be the upper limit of the previous one:
1) 800 + 200= 100
First interval [800; 1000)
2) 1000 + 200
Second interval
[1000; 1200)
And so on until you reach the maximum value of the data set,
[1200; 1400)
[1400; 1600)
[1600; 1800)
[1800; 2000)
[2000; 2200)
Then you have to order the data from least to greatest and count how many observations correspond to each value, this way you'll determine the observed frequency for each interval.
Table and histogram in second attachment.
b.
As you can see in the histogram, this distribution is symmetrical centered in the interval [1400; 1600) and there are no outliers observed.
c.
Values around 1400-1600 are the most common ones while scores around 800-1000 or 2000-2200 are more uncommon, in this sample it seems the probability to obtain a perfect score for the combined three-part SAT is extremely low.
I hope you have a nice day!
Answer:
![v=364.5\ m^3](https://tex.z-dn.net/?f=v%3D364.5%5C%20m%5E3)
Step-by-step explanation:
<u>Volume Of A Regular Solid</u>
When a solid has a constant cross-section, the volume can be found by multiplying the area of the base by the height. The area of a trapezium is
![\displaystyle A_t=\frac{b_1+b_2}{2}h](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A_t%3D%5Cfrac%7Bb_1%2Bb_2%7D%7B2%7Dh)
where
and
are the lengths of the parallel sides and h the distance between them.
The figure shows a solid with a trapezoid as the constant cross-section and a height x. The volume of the solid is
![\displaystyle v=A_t\ x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3DA_t%5C%20x)
![\displaystyle v=\frac{b_1+b_2}{2}\ h\ x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3D%5Cfrac%7Bb_1%2Bb_2%7D%7B2%7D%5C%20h%5C%20x)
The image doesn't explicitly say if the length of 4.5 is the height of the trapezium or the length of that side. We'll assume the first, so our data is:
![\displaystyle b_1=7m,\ b_2=11m,\ h=4.5m,\ x=9m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20b_1%3D7m%2C%5C%20b_2%3D11m%2C%5C%20h%3D4.5m%2C%5C%20x%3D9m)
We now compute the volume
![\displaystyle v=\frac{7+11}{2}.(4.5)(9)=364.5](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3D%5Cfrac%7B7%2B11%7D%7B2%7D.%284.5%29%289%29%3D364.5)
![\boxed{\displaystyle v=364.5\ m^3}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdisplaystyle%20v%3D364.5%5C%20m%5E3%7D)