1 year ago

(49p2–490p) ÷(p–10) please help!!

Mathematics

1 answer:

horsena [70]1 year ago

8 0

Answer:

(49p2–490p) ÷(p–10)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

What is the following product?

KiRa [710]

ANSWER

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

EXPLANATION

The given product is:

$( \sqrt{14} - \sqrt{3} )( \sqrt{12} + \sqrt{7} )$

We expand using the distributive property to obtain:

$\sqrt{14}( \sqrt{12} + \sqrt{7}) -\sqrt{3}( \sqrt{12} + \sqrt{7} )$

Extract the perfect squares to get:

$\sqrt{14}(2 \sqrt{3} + \sqrt{7}) -\sqrt{3}( 2\sqrt{3} + \sqrt{7} )$

Expand further to get;

$2 \sqrt{42} +7 \sqrt{2}- 2(3) - \sqrt{21}$

This simplifies to,

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

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3 years ago

Whats the value of x?

coldgirl [10]

Bro the value of x is 84

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3 years ago

Today the price of a Jeep is $25,000. In 1970, the price was $5,000. What's the price relative?

IgorC [24]

Answer:

$500

Step-by-step explanation:

Today the price of a Jeep is $25,000.

In 1970, the price was $5,000.

We need to find the relative price. It can be calculated as follows :

$P=\dfrac{25000}{5000}\times 100\\\\P=\$500$

So, the relative price is $500.

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3 years ago