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Travka [436]
2 years ago
12

Using a chemical equation to find moles of product from moles of reactant

Chemistry
1 answer:
kumpel [21]2 years ago
3 0

Answer:

0.86 moles H₂O

Explanation:

To solve this problem, it is important to first determine the balanced chemical equation. The balanced equation is necessary as it will provide the mole-to-mole ratio needed to convert between moles O₂ and moles H₂O.

The unbalanced equation:

C₈H₁₈ (l) + O₂ (g) ---> CO₂ (g) + H₂O (g)

<u>Reactants:</u> 8 carbon, 18 hydrogen, 2 oxygen

<u>Products:</u> 1 carbon, 2 hydrogen, 3 oxygen

As you can see, the equation is not balanced because there are unequal amounts of each element on both sides. Balancing the equation is a matter of guessing-and-checking to see which combination of coefficients work.

The balanced equation:

2 C₈H₁₈ (l) + 25 O₂ (g) ---> 16 CO₂ (g) + 18 H₂O (g)

<u>Reactants:</u> 16 carbon, 36 hydrogen, 50 oxygen

<u>Products:</u> 16 carbon, 36 hydrogen, 50 oxygen

Now that the equation is balanced, we can use the coefficients of O₂ and H₂O to construct our mole-to-mole ratio and perform our conversion. The final answer should have 2 sig figs to match the given value (1.2 moles). The state of matter is most likely not necessary to include in your final answer.

1.2 moles O₂          18 moles H₂O
---------------------  x  -----------------------  =  0.86 moles H₂O
                                25 moles O₂

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A. Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculat
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Answer:

A)Mass of  gallium plated out is 0.3440 grams

B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

Explanation:

To calculate the total charge, we use the equation:

C=I\times t

where,

C = Charge

I = Current in time t (seconds)

To calculate the moles of electrons, we use the equation:

\text{Moles of electrons}=\frac{C}{F}

where,

F = Faraday's constant = 96500

A) The equation for the deposition of Ga(s) from Ga(III) solution follows:

Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)

I = 0.790 A, t = 30.0 min = 1800 seconds

C=I\times t

C=0.790 A\times 1800 s=1422 C

Moles of electron transferred:

=\frac{1422 C}{96500 F}=0.01474 mol

Now, to calculate the moles of gallium, we use the equation:

\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}

n = number of electrons transferred = 3

\text{Moles of Gallium}=\frac{0.01474 mol}{3}=0.004913 mol

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B) The equation for the deposition of Sn(s) from Sn(II) solution follows:

Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)

Moles of tin = \frac{8.70 g}{119 g/mol}=0.07311 mol

n = number of electrons transferred = 2

\text{Moles of tin}=\frac{\text{Moles of electrons}}{n}

Moles of electron =  n\times \text{Moles of tin}

=2\times 0.07311 mol=0.14622 mol

Charge transferred during time t :

\text{Moles of electrons}=\frac{C}{F}

C=96500 F\times 0.14622 mol=14,110.23 C

Current applied for t time = I = 5.79 A

t=\frac{C}{I}=\frac{14,110.23 C}{5.79 A}=2,437 s=0.67 hrs

For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

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Answer:

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