Question

Suppose you are given a triangle with hypotenuse of length 2 and legs of length x+1 and x-1 . Find the numerical length of both sides.

Answer 1

Answer:

Step-by-step explanation:

$(2)^2=(x+1)^2+(x-1)^2$

By solving this equation we can get:

$x=1 \\x=-1 (Impossible)$

∴