Answer:
y=-3/16(x-8)^2+12
Step-by-step explanation:
Refer to the vertex form equation for a parabola:
y=a(x-h)^2+k where (h,k) is the vertex.
Therefore, we have y=a(x-8)^2+12 as our equation so far. If we plug in (16,0) we can find a:
0=a(16-8)^2+12
0=64a+12
-12=64a
-12/64=a
-3/16=a
Therefore, your final equation is y=-3/16(x-8)^2+12
Answer:
-sqrt(3) -i = 2 cis (7pi/6)
Step-by-step explanation:
-sqrt(3) -i
We can find the radius
r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)
= sqrt( 3 + 1)
= sqrt(4)
= 2
theta = arctan (y/x)
arctan (-1/-sqrt(3))
arctan (1/sqrt(3))
theta = pi/6
But this is in the first quadrant, and we need it in the third quadrant
Add pi to move it to the third quadrant
theta = pi/6 + 6pi/6
=7pi/6
-sqrt(3) -i = 2 cis (7pi/6)
Answer:
sorry hindi ko alam hirapuwu
Answer:
Step-by-step explanation:
<u>Use ratios:</u>
- 7.5 mots / 37.5 parlings = 13 mots / x parlings
- x = 13*37.5/7.5
- x = 65
