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zhenek [66]
1 year ago
7

1. In the process of solving the radical equation, x − 5 =radical 3x −11 , you will need to solve which of the following quadrat

ic equations?
a) x2 −7x+16=0
b) x2 −3x−14=0
c) x2 +13x−36=0
d) x2 −13x + 36 = 0 e)
none of these
Mathematics
1 answer:
Goryan [66]1 year ago
8 0

In the process of solving the expression x − 5 =radical 3x −11 , you will need to solve the quadratic equation x² - 13x + 36 =0

<h3>Solving radical equations</h3>

Radical equations are expression that are under the square root. For instance √x is a radical expression.

Given the equation expressed as:

x − 5 = √3x −11

Square both sides to have;

(x-5)² = (√3x −11 )²

This can be further expressed as:

(x-5)² =3x −11

Expand

x² -10x + 25 = 3x - 11

Equate to zero

x² -10x + 25 - 3x +11 = 0
x² -10x - 3x +36 = 0
x² - 13x + 36 =0

Hence in the process of solving the expression x − 5 =radical 3x −11 , you will need to solve the quadratic equation x² - 13x + 36 =0

Learn more on radical expressions here: brainly.com/question/6755932

#SPJ1

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Answer:

The answer is below

Step-by-step explanation:

Pythagoras theorem states that for a right angled triangle, the square of the hypotenuse side is equal to the sum of the square of the remaining sides. The hypotenuse is the longest side (that is side opposite to the 90° angle).

In right angle triangle ABD:

AB² = AD² + BD²     (1)

In right angle triangle ACD:

AC² = AD² + CD²      (2)

Also:

AC² + AB² = BC²       (3)

But BC = BD + CD

AC² + AB² = (BD + CD)²     (4)

Adding equation 1 and 2 gives:

AB² + AC² = (AD² + BD²) + (AD² + CD²)  

AB² + AC² = 2AD² + BD² + CD²

substituting AC² + AB² = (BD + CD)²:

(BD + CD)² = 2AD² + BD² + CD²

BD² + 2(BD)(CD)+ CD² = 2AD² + BD² + CD²

2AD² = 2(BD)(CD)

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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