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Lunna [17]
2 years ago
8

What is the name of this hydrocarbon?

Chemistry
2 answers:
Phoenix [80]2 years ago
5 0

Answer:

alkanes alkens alkenes and a bromatic hydrocarbons

ycow [4]2 years ago
4 0

Answer:

\huge\boxed{\sf Pentane}

Explanation:

<h3><u>The given compound has:</u></h3>
  • 5 carbons
  • all single bonds

Prefix for 5 carbons = Pent

Suffix for all single bonds = ane (since the compound is alkane)

<u>So, the name of this hydrocarbon is:</u>

<h3>Pentane</h3>

\rule[225]{225}{2}

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goblinko [34]

Answer:

The actual value = 25.7 ml

The error = 15.6%

This means that the value of error = 0.156 * 25.7 = 4.0092 ml

Now, the error percentage found means that the student got the value either greater than the actual one with the value of error or less than the actual one with the value of error.

This means that the two possible readings are:

either : 25.7 + 4.0092  = 29.7092 ml

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7 0
3 years ago
Propane burns in oxygen to produce carbon dioxide and water what is the percent yeild
amid [387]

Answer:

The percentage yield is 78.2g

Explanation:

Given, mass of propane = 42.8 g , sufficient O2 percent yield = 61.0 % yield.

Reaction - C3H8(g)+5O2(g)------> 3CO2(g)+4H2O(g)

First we need to calculate the moles of propane

Moles of propane = \frac{42.8}{44.096} g.mol-1

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So, moles of CO2 from the moles of propane

1 mole of C3H8(g) = 3 moles of CO2(g)

So, 0.971 moles of C3H8(g) = ?

= 2.913 moles of CO2

So theoretical yield = 2.913 moles \times 44.0 g/mol

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So, the actual mass of CO2 = percent yield \times  theoretical yield / 100 %

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the mass of CO2 that can be produced if the reaction of 42.8 g of propane and sufficient oxygen has a 61.0 % yield is 78.2 g

4 0
3 years ago
A squirrel ran 20 meters along the fence at a constant speed for 10
Black_prince [1.1K]

Answer:

It's D

Explanation:

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