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2 years ago

What is the acid name for H(HS) need help asap

Chemistry

1 answer:

natali 33 [55]2 years ago

4 0

The acid name for H(HS) is hydrogen sulfide.

<h3>Properties of hydrogen sulfid</h3>

Hydrogen sulphide is an example of a weak acid that is form by the exposure of many metals and non metals to water.

The International Union of Pure and Applied Chemistry (IUPAC) acidic name for H( HS) is hydrogen sulfide. But is also called sulfane, sulfur hydride, sour gas, sulfurated hydrogen, hydrosulfuric acid.

The properties of hydrogen sulfide include:

In low concentrations it smells like rotten eggs,

H(HS) is soluble in water and many other liquids,

H(HS) is highly explosive,l

H(HS) is colourless and has a reflective ratio very similar to that of air.

Therefore, the acid name for H(HS) is hydrogen sulfide.

Learn more about hydrogen sulfide here:

brainly.com/question/13469013

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What is an example of a Low Energy-created depositional environment?

sweet-ann [11.9K]

Answer:

River flood plains, swamps, lakes, lagoons, marshes, and offshore.

Explanation:

Slow-moving currents prevent coarse-grained sediment from migrating into low-energy depositional environments. Fine materials can be carried long distances before they can settle out in the absence of waves and currents.

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3 years ago

After 42 days, a 2.0 g sample of phosphorous-32 contains only 0.25 g of the isotope. What is the half-life of phosphorus-32?

tester [92]

Answer:

Half life of phosphorous-32 = 14 days

Explanation:

Given data:

Total mass of phosphorous-32 = 2.0 g

After 42 days mass left = 0.25 g

Half life of phosphorous-32 = ?

Solution:

First of all we will calculate the number of half lives passed.

At time zero = 2.0 g

At first half life = 2.0 g/2 = 1.0 g

At 2nd half life = 1.0 g/2 = 0.5 g

At 3rd half life = 0.5 g/2 = 0.25 g

Half life:

Half life = T elapsed / half lives

Half life = 42 days/ 3

Half life = 14 days

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3 years ago

If the quantity of reactants used in a chemical reaction increase, then the quantity of the products produced will also be incre

oksian1 [2.3K]

Answer:

the amount of reactants is always directly proportional to the product

Explanation:

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4 years ago

Why are non-metals dull in appearance as solids?

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4 years ago

If 6.35 g of cu(no3)2 is dissolved in water to make a 0.750 m solution, what is the volume of the solution (in ml)?

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First, we need to find out how many moles we have of $Cu ( NO_{3} )_{2}$ if we are given 6.35g.

We need to calculate the molar mass of the molecule:

Cu: 63.546g
N: 14.01g * 2 = 28.02g
O: 15.999g * 6 = 95.994

Add them together to get: 187.56g

So now we need to find the number of moles we are given. This can be done by setting up a multiplication equation and cancelling the units:

$\frac{1mole}{187.56g}* \frac{6.35g}{1}=0.034 mol _{Cu( NO_{3} )_{2} }$

So now that we know the number of moles that we have, we can use the molarity equation to find the volume of the solution. The molarity equation is:

$Molarity= \frac{moles}{Liters}$

So since we are given the molarity in the equation (0.750 M), we can plug in the molarity and moles to find the volume of the solution:

$0.750= \frac{0.034mol}{volume(L)}$

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So now we know that the volume is 0.04533 Liters; however the question asks for the answer in milliliters. To do this, we must multiply by 1000:

$\frac{0.045L}{1} * \frac{1000mL}{1L}=45.33mL$

So the volume of the solution (in mL) is 45.33 mL.

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3 years ago