Nickel (Ni) has the charge as +3 while oxygen (O) has -2. Hence, the chemical formula for the nickel (iii) oxide is Ni₂O₃.
molar mass of Ni = 58.69 g/mol
molar mass of O = <span>15.99 g/mol
number of Ni atoms in </span>Ni₂O₃ = 2
Molar mass of Ni in Ni₂O₃ = 2 x 58.69 g/mol = 117.38 g/mol
number of O atoms in Ni₂O₃ = 3
Molar mass of O in Ni₂O₃ = 3 x 15.99 g/mol = 47.97 g/mol
Hence, molar mass of compound = 117.38 g/mol + 47.97 g/mol
= 165.35 g/mol
=<span> 165.4 g/mol</span>
Answer:
1.07×10²¹ molecules are needed to sound the alarm
Explanation:
Let's convert the mass of CO to moles, to determine the amount of molecules.
0.05 g . 1 mol / 28 g = 1.78×10⁻³ moles
Now we can determine the number of molecules with the NA
1 mol has 6.02×10²³ molecules
1.78×10⁻³ moles may have (1.78×10⁻³ . 6.02×10²³) / 1 = 1.07×10²¹ molecules
Answer:
<u>the reaction will shift to the left </u>and produce more reactants
Explanation:
Step 1: data given
Kc = 190
Temperature = 1000 K
[CO] = 0.025 M
[H2] = 0.045 M
[H2O] = 0.025 M
[CH4] = 0.046 M
When Q=Kc, the system is at equilibrium and there is no shift to either the left or the right.
When Q<Kc, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.
When Q>Kc, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants
Step 2: The balanced equation
CO(g) + 3 H2(g) ⇌ H2O(g) + CH4(g)
Step 3: calculate Q
Q = [H2O][CH4] / [CO][H2]³
Q = (0.025*0.046) / (0.025*0.045³)
Q = 504.8
Q > Kc
This means there are more products than reactants. To decrease the amount of products, <u>the reaction will shift to the left </u>and produce more reactants
Answer:
Chemistry is the science of matter, its properties, structure, changes or reactions and the energy that accompanies these changes.
