Answer:
Increasing if f' >0 and decreasing if f'<0
Step-by-step explanation:
Difference quotient got by getting
will be greater than 0 if function is increasing otherwise negative
Here h is a small positive value.
In other words, we find that whenever first derivative of a function f(x) is positive the function is increasing.
Here given that for x1, x2 where x1<x2, we have
if f(x1) <f(x2) then the function is decreasing.
Or if x1<x2 and if f(x1) >f(x2) for all x1, and x2 in I the open interval we say f(x) is decreasing in I.
(x+5,y-6) is the coordinate notation.
If the two diagonals are 
and 
, the are of the rhombus is
So, in your case, the area is
The other options are wrong because:
- option A doens't divide by 2, thus getting twice the area of the rhombus
- option B summed the diagonals instead of multiplying them
- option D took the difference of the diagonals.
Use the metric relations,
AC*CD=BC^2
=>
5*CD=9^2
solve for CD
CD=9*9/5=16.2
You have a 1 in 50 chance (ie A)
Explanation:
Let's start with the first bag. In it sits 5 numbers. So, you have a 1 in 5 chance that the number picked will be yours.
Now, let's consider the second bag. You have 10 different numbers and only one of yours may be picked. Hence, you have a 1 in 10 chance that yours will get picked.
Since we want them simultaneously, we will need to multiply the two probabilities together, yielding a 1 in 50 chance.
