Answer:
A. How can the equation be used in temperature conversion?
You take the conversion equation C = (5/9) (F - 32) and you replace the F by the value of Fahrenheit degrees... then solve the calculations to get the degrees in Celsius.
For example, if you have 80°F to convert in °C:
C = (5/9) (80 - 32) = (5/9) (48) = 26.66 °C
B. How can you use the graph to find the body temp in C?
Using the graph will give a very imprecise measure due the scale of the graph.
But you would have to find 98.6 on the axis of X (it represents the °F), then go upwards until you find the line....
Then report that position on the line on the Y-axis (representing the °C) to get your measure.
Answer:
Either one: the two line have a point in common, or infinite: they are the same line.
Answer:
Step-by-step explanation:
The string of a kite forms a right angle triangle with the ground. The length of the string represents the hypotenuse of the right angle triangle. The height of the kite represents the opposite side of the right angle triangle.
To determine the height of the kite, we would apply the sine trigonometric ratio which is expressed as
Sin θ = opposite side/hypotenuse.
1) if the kite makes an angle of 25° with the ground, then the height, h would be
Sin 25 = h/50
h = 50Sin25 = 50 × 0.4226
h = 21.1 feet
2) if the kite makes an angle of 45° with the ground, then the height, h would be
Sin 45 = h/50
h = 50Sin45 = 50 × 0.7071
h = 35.4 feet
The approximate difference in the height of the kite is
35.4 - 21.1 = 14.3 feet
Answer:
x = -3
y = 0
Step-by-step explanation:
<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>
<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>
<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>
<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>
<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>
<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>
<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>
<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>
<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>
<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>
<u>
</u>
<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>
<u>Equating</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>
<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>
<u>
</u>
4y - 6 = -6 + 3y
4y - 3y = -6 + 6
y = 0
Putting value of y in ( iii )
x = 2y - 3
x = 2 ( 0 ) - 3
x = -3