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Alexeev081 [22]
3 years ago
7

How are gravity and electromagnetic force similar and different?

Physics
1 answer:
oksano4ka [1.4K]3 years ago
7 0

Answer:

The biggest difference is that gravity is an attractive force while electromagnetism is both an attractive and repelling force. Gravity happens between two objects depending on their masses, while electromagnetism is dependent on the objects' electric charges and the distance between them.

Explanation:

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The repulsive force between two protons has a magnitude of 2.00 N. What is the distance between them?
Aloiza [94]

Answer:

The answer to your question is letter A.     r = 1.07 x 10⁻¹⁴ m

Explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

                 F = K\frac{q1q2}{r^{2}}

Solve for r

                r = \sqrt{\frac{kq1q2}{F}}

Substitution

                r = \sqrt{\frac{8.987 x 10^{9}x1.6 x 10^{-19} x 1.6 x 10x^{-19}}{2}}

Simplification

                r = \sqrt{\frac{2.3 x 10^{-28}}{2}}

                r = \sqrt{1.15 x 10^{-24}}

Result

                r = 1.07 x 10⁻¹⁴ m

6 0
3 years ago
Read 2 more answers
Heat transfer within a fluid takes place by
lilavasa [31]
I think its b not sure
3 0
3 years ago
According to Bernoulli's fluid formula a An increase in the speed will lower the internal pressure b An increase in the speed wi
lorasvet [3.4K]

Answer:

a An increase in the speed will lower the internal pressure

Explanation:

Bernoulli's fluid formula

P_1+\frac{1}{2}\rho v_1^2+\rho gh_1=P_1+\frac{1}{2}\rho v_2^2+\rho gh_2

where

P = Pressure

ρ = Density of fluid

g = Acceleration due to gravity

h = Height

v = Velocity of fluid

If there is no change in height then we get

P_1+\frac{1}{2}\rho v_1^2=P_1+\frac{1}{2}\rho v_2^2\\\Rightarrow P+\frac{1}{2}\rho v^2=constant

According to the Bernoulli's principle when the speed of the fluid is larger in a region of streamline flow the pressure is smaller in that region. From the above equation it can be seen that increase in speed should simultaneously reduce pressure in order for their sum to be constant.

5 0
3 years ago
A constant horizontal force F is applied to a 5 kg box on a frictionless horizontal surface. The box starts from rest and moves
sergejj [24]
65(58)+85)6463(9786+)9_43=
7 0
3 years ago
A hockey puck has a mass of 0.107 kg and is at rest. A hockey player makes a shot, exerting a constant force of 28.0 N on the pu
gregori [183]

Answer:

The speed does it head toward the goal = 41.87 \frac{m}{s}

Explanation:

Mass = 0.107 kg

Initial velocity ( u ) = 0

Force (F) = 28 N

Time = 0.16 sec

From newton's second law,  Force  = mass × acceleration

⇒  F = m × a

⇒  28 = 0.107 × a

⇒  a = 261.7 \frac{m}{s^{2} } --------- (1)

This is the value of acceleration.

Final speed of the mass is calculated by the equation V = U + at

⇒ U = 0 because mass in in rest position at start.

⇒ V = a t

Put the values of acceleration and time in above formula we get

⇒ V = 261.7 × 0.16

⇒ V = 41.87 \frac{m}{s}

Therefore the speed does it head toward the goal = 41.87 \frac{m}{s}

5 0
3 years ago
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