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2 years ago

A variable is normally distributed with mean 6 and standard 2 deviation .

1 answer:

8 0

The normal distribution is also known as the Gaussian distribution. The percentage of all possible values of the variable that are less than 4 is 15.87%.

<h3>What is a normal distribution?</h3>

The normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution about the mean, indicating that data near the mean occur more frequently than data distant from the mean. The normal distribution will show as a bell curve on a graph.

A.) The percentage of all possible values of the variable that lie between 5 and 9.

P(5<X<9) = P(X<9) - P(5<X)

= P(z<1.5) - P(-0.5<z)

= 0.9332 - 0.3085

= 0.6247

= 62.47%

B.) The percentage of all possible values of the variable that exceed 1.

P(X>1) = 1 - P(X<-2.5)

= 1-0.0062

= 0.9938

= 99.38%

C.) The percentage of all possible values of the variable that are less than 4.

P(X<4) = P(X <4)

= P(z<-1)
= 0.1587

= 15.87%

Learn more about Normal Distribution:

brainly.com/question/15103234

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Given function $h(t)=-16t^2+15t+6.5$

To find the value of h(t) when $t=\frac{15}{32}$ :

$h(t)=-16t^2+15t+6.5$

Substitute $t=\frac{15}{32}$ in the given function.

$$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5$

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Now multiply the common terms into inside the bracket.

$$=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5$

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