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Vera_Pavlovna [14]

1 year ago

14

Please help! To solve the equation 1.75n = 7 for n, what operation must be applied to both sides in order to isolate the variabl

e n?

2 answers:

Kazeer [188]1 year ago

6 0

Answer:

C

Step-by-step explanation:

1.75n = 7 ( to isolate n divide both sides by 1.75 )

n = $\frac{7}{1.75}$ = 4

marysya [2.9K]1 year ago

6 0

Answer:

c.) Divide by 1.75

Step-by-step explanation:

Given equation:

⇒ 1.75n = 7

Here the coefficient of n which is 1.75 needs to be removed. There is only one way of doing that - by dividing both sides by 1.75.

When done so:

⇒ 1.75n/1.75 = 7/1.75

⇒ n = 4

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Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$

Substitute:

$\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}$

Combine fractions:

$\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}$

Simplify:

$6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}$

Q.E.D.

6 0

2 years ago

7W + 3 = -4W - 85 <br><br>a. -11<br>b. 11<br>c. 8<br>d. -8<br>

mylen [45]

-8
Step 1) Subtract 3 from both sides of the equation
Step 2) Add 4W to both sides of the equation
Step 3) Divide both sides of the equation by the same factor

6 0

2 years ago

Will mark brainliest geometry proof ............................

photoshop1234 [79]

The order is
CPCTC
SAS
SAS

7 0

3 years ago

Katie is buying souvenir.gifts for her big family back home. She wants to buy everyone either a key chain or a magnet. The magne

NikAS [45]

The total number of gifts = x+y.
The inequality is:
$x+y \geq 24$

Key chains cost $1, Magnets $0.50
Total Cost = x + 0.5y
Inequality is:
$x+0.5y \leq 20$

Without graphing you can solve system by using substitution:
$y = 24 - x \\ \\ x + 0.5(24-x) = 20 \\ \\ 0.5x +12 = 20 \\ \\ x = 16 \\ \\ y = 24-16 = 8$

This is one solution where the maximum x value is given.
So the most keychains that can be purchased is 16. However, because magnets are cheaper, more can be purchased as long as cost remains under 20.

If you solve both inequalities for "y", you get the upper and lower bounds for how many magnets can be purchased given a quantity of keychains.

$24-x \leq y \leq 40 -2x \\ \\ x \leq 16$

This is complete solution which gives all possible combinations.
(Graph is Attached)

6 0

3 years ago

Anyone know how to do this? If so plz help

bekas [8.4K]

NOTES:

Use the equation y = mx + b where m is the unit rate and b is the one-time flat fee

1. Answer:

$\begin {array}{c||c|c|c|c}x&0&1&2&3\\ y&70.00&70.20&70.40&70.60\\\end{array}$

<u>Step-by-step explanation:</u>

coffee maker costs $70 - this is a one-time flat fee

it costs $0.20 per cup of coffee - this is the unit rate

y = 0.20x + 70

y = 0.20(0) + 70 → y = 0.00 + 70 → y = 70.00

y = 0.20(1) + 70 → y = 0.20 + 70 → y = 70.20

y = 0.20(2) + 70 → y = 0.40 + 70 → y = 70.40

y = 0.20(3) + 70 → y = 0.60 + 70 → y = 70.40

*******************************************************************************

2. Answer:

$\begin {array}{c||c|c|c|c}x&1&2&3&4\\ y&4.50&6.00&7.50&9.00\\\end{array}$

<u>Step-by-step explanation:</u>

shoes costs $3.00 - this is a one-time flat fee

it costs $1.50 per game of bowling - this is the unit rate

y = 1.50x + 3.00

y = 1.50(1) + 3.00 → y = 1.50 + 3.00 → y = 4.50

y = 1.50(2) + 3.00 → y = 3.00 + 3.00 → y = 6.00

y = 1.50(3) + 3.00 → y = 4.50 + 3.00 → y = 7.50

y = 1.50(4) + 3.00 → y = 6.00 + 3.00 → y = 9.00

*******************************************************************************

3. Answer: Negative

<u>Step-by-step explanation:</u>

As the x-values increase, the y-values decrease. Opposite directions results in a negative slope.

*******************************************************************************

4. Answer: Gym A → y = 20x + 50 Gym B → y = 25x + 30

<u>Step-by-step explanation:</u>

Use the slope formula: $m = \dfrac{y_2-y_1}{x_2-x_1}$ . Then choose ONE of the points and input the point (x₁, y₁) and slope (m) into the Point-Slope formula: y - y₁ = m(x - x₁) and solve for y.

Gym A: (x₁, y₁) = (1, 70) and (x₂, y₂) = (2, 90)

$m=\dfrac{90-70}{2-1} = \dfrac{20}{1} = 20$

y - 70 = 20(x - 1)

y - 70 = 20x - 20

y = 20x + 50

Gym B: (x₁, y₁) = (1, 55) and (x₂, y₂) = (2, 80)

$m=\dfrac{80-55}{2-1} = \dfrac{25}{1} = 25$

y - 55 = 25(x - 1)

y - 55 = 25x - 25

y = 25x + 30

5 0

3 years ago