Solve the system of equations using the elimination method. 1.Solve {x + 3y = -15
1 answer:
An equation is formed of two equal expressions. The solution is (-9,-2).
<h3>What is an equation?</h3>An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Given the equation x + 3y = -15 and -3x + 2y = 23,
Step 1- Multiply the equations to make the coefficients match in either the x- or y-variable.
x + 3y = -15
3x + 9y = -45
Step2- After you multiply, add or subtract the two equations.
3x + 9y -3x + 2y = -45 + 23
Step 3- Then solve for the variables that is left.
11y = -22
y = -2
Step4- Substitute the value of y in any one of equations to solve for x.
x + 3(-2) = -15
x - 6 = -15
x = -9
Hence, The solution is (-9,-2).
Learn more about Equation:
#SPJ1
You might be interested in
Your question can be quite confusing, but I think the gist of the question when paraphrased is: P<span>rove that the perpendiculars drawn from any point within the angle are equal if it lies on the angle bisector?
Please refer to the picture attached as a guide you through the steps of the proofs. First. construct any angle like </span>∠ABC. Next, construct an angle bisector. This is the line segment that starts from the vertex of an angle, and extends outwards such that it divides the angle into two equal parts. That would be line segment AD. Now, construct perpendicular line from the end of the angle bisector to the two other arms of the angle. This lines should form a right angle as denoted by the squares which means 90° angles. As you can see, you formed two triangles: ΔABD and ΔADC. They have congruent angles α and β as formed by the angle bisector. Then, the two right angles are also congruent. The common side AD is also congruent with respect to each of the triangles. Therefore, by Angle-Angle-Side or AAS postulate, the two triangles are congruent. That means that perpendiculars drawn from any point within the angle are equal when it lies on the angle bisector
Please refer to the picture attached as a guide you through the steps of the proofs. First. construct any angle like </span>∠ABC. Next, construct an angle bisector. This is the line segment that starts from the vertex of an angle, and extends outwards such that it divides the angle into two equal parts. That would be line segment AD. Now, construct perpendicular line from the end of the angle bisector to the two other arms of the angle. This lines should form a right angle as denoted by the squares which means 90° angles. As you can see, you formed two triangles: ΔABD and ΔADC. They have congruent angles α and β as formed by the angle bisector. Then, the two right angles are also congruent. The common side AD is also congruent with respect to each of the triangles. Therefore, by Angle-Angle-Side or AAS postulate, the two triangles are congruent. That means that perpendiculars drawn from any point within the angle are equal when it lies on the angle bisector