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Kazeer [188]
2 years ago
12

Please help please and thank you

Mathematics
1 answer:
SpyIntel [72]2 years ago
8 0

Answer:

B or the second option

Step-by-step explanation:

We can label the diagram parts A-E to fully represent the situation in the question.

A: Julie's ascent up the mountain (moving/increasing)

B: Julie drinking hot chocolate (stationary/constant)

C: Julie's descent down the mountain (moving/decreasing)

D:  Julie rests (stationary/constant)

E:  Julie's final descent down the mountain (moving/decreasing)

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Can anybody help me out
VashaNatasha [74]

Answer:

1. There are 8 big fish for every 10 small fish.

2. There are 4 big fish for every 5 small fish.

5 0
4 years ago
Graham paid $87.45 for a pair of jeans. This amount included a tax of 40%. What was the cost of the jeans before tax?
kiruha [24]

The final price is the cost plus the tax.

Since we know the tax and a percent, we can write this as

T = C(1+r)

T = what Graham paid = $87.45

C = cost before tax

r = tax rate expressed as a decimal = .40

Plugging in what we know

87.45 = C (1+.4)

87.45 = C(1.4)

Divide both sides by 1.4

C = $62.46

5 0
3 years ago
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
4 years ago
What unfortunate mistake did the champion ice skater make with his gold medal
Fed [463]

Answer:

He Had It Bronzed

Step-by-step explanation:

Hope this help pls mark as brainlest!!

5 0
3 years ago
PLEASE ANSWER QUICK I WILL GIVE BRAINLISEST
slava [35]

Answer:

ohhh no typon hope it helps

5 0
3 years ago
Read 2 more answers
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