1 year ago

Evaluate 2 p-q when p=17 and q=3.

Mathematics

1 answer:

BigorU [14]1 year ago

4 0

Final answer:

The value of the expression is 31.

Step-by-step explanation:

Substitution is a process of putting the values of variable in the expression.

Given: p=17 and q=3

To find: value of 2p-q

We will substitute the values and simplify.

Putting the values of variables in the expression as

2p-q = 2x17-3 =34-3 = 31

For more check here: brainly.com/textbook-solutions/q-2-evaluate-2-p-q-p-17-q-govvt8

You might be interested in

How to solve 2/2/7 2/1/7?

Gala2k [10]

Ok so the slashes are division so you would divide

6 0

3 years ago

Benny bought nine new baseball trading cards to add to his collection. The next day his dog ate half of his collection. There ar

hjlf

9+x

divided by

x=61

3 0

2 years ago

Read 2 more answers

How are problems like these solved

Flura [38]

the angles on the opposite sides of a quadrilateral touching the circumference adds up to 180 degrees

so,

(21x-2) + (38x +5) = 180

21x+38x −2+5=180

59x+3=180

59x=177

x=3

4 0

2 years ago

Question number 8. Prove that 3 + √5 is an irrational number.

Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

$\\ \sf \: 3 + \sqrt{5} = \frac{a}{b} \\ \\ \qquad \: \tiny \sf{(where \: \: a \: \: and \: \: b \: \: are \: \: integers \: \: and \: \: b \: \neq \: 0)} \\$

$\\ \sf \: \sqrt{5} = \frac{a}{b} - 3 = \frac{a - 3b}{b} \\$

Since, a, b and 3 are integers. So,

$\\ \sf \: \frac{p - 3b}{b} \\ \\ \qquad \tiny \sf{ \: (is \: \: a \: \: rational \: \: number \:) } \\$

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

$\\$

Hence, 3 + √5 is an irrational number.

7 0

3 years ago

Last year I read 120 books. This year I want to increase that by 55%.

Leto [7]

Answer:

186?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers