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1 year ago

The class-mark of the class 80-90 is

Mathematics

1 answer:

mixas84 [53]1 year ago

6 0

Answer:

maths/hindi

Step-by-step explanation:

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CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION

Murljashka [212]

Answer:

The value of DC is 66.34.

Step-by-step explanation:

The triangles ABC and DCA are right angled triangles.

The straight line AC is a bisector for angles C and A.

The measure of ∠C is 30°.

Then the measure of angles BCA and ACD will be 15° each.

The measure of angle DAB is 150°.

Then the measure of angles DAC and BAC will be 75° each.

Now consider the right angled triangle ABC.

The measure of side AC is:

$AC^{2}=AB^{2}+BC^{2}\\AC=\sqrt{AB^{2}+BC^{2}}\\=\sqrt{4^{2}+(10\sqrt{3})^{2}}\\=\sqrt{316}$

Consider the right angled triangle DCA.

The angle DAC measure 75°.

Using the trigonometric identities compute the value of Perpendicular DC as follows:

$tan\ 75^{o}=\frac{DC}{\sqrt{316}}\\\\DC=3.732\times\sqrt{316}\\\\DC=66.34$

Thus, the value of DC is 66.34.

7 0

2 years ago

Write the equation of the line with slope =7 and y- intercept= -1

Aliun [14]

Answer:

y = 7x - 1 is the answer to the question

4 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

liubo4ka [24]

Answer:

1) 20.9

2) 896

3) 21

Step-by-step explanation:

1) 5.6÷2^3+(12.75+7.45)

---> 12.75 + 7.45 = 20.2

$5.6$ ÷ $2^3 + 20.2$

--> Simplify 2^3 to 8

$5.6$ ÷ 8 + 20.2

--> 5.6 ÷ 8 = 0.7

$0.7+20.2$

--> Simplify

$20.9$

2) 4^3 × (0.6 +3.6) ÷ 0.3

---> 0.6 + 3.6 = 4.2

4^3 * 4.2 ÷ 0.3

---> 4^3 = 64

64 * 4.2 ÷ 0.3

--> 64 * 4.2 = 268.8

268.8 ÷ 0.3

--> 268.8 ÷ 0.3 = 896

896

3) 2^4 + (2.75 +1.75) ÷ 0.9

--> 2.75 + 1.75 = 4.5

2^4 + 4.5 ÷ 0.9

--> 2^4 = 16

16 + 4.5 ÷ 0.9

--> 4.5 ÷ 0.89 = 5

16 + 5

--> Simplify

= 21

8 0

1 year ago

I didn't get how you wrote 1.75 like how did it come there?

sertanlavr [38]

Answer:

Uhh what??

Step-by-step explanation:

Do you mean like 1.75 in a decimal form??

4 0

2 years ago

59-(2c+3)=4(c+7)+c.

alisha [4.7K]

Step-by-step explanation:

${:}\leadsto$ $\sf 59-(2c+3)=4 (c+7)+c$

${:}\leadsto$ $\sf 59-2c-3=4c+28+c$

${:}\leadsto$ $\sf 56-2c=5c+28$

${:}\leadsto$ $\sf 5c+28=56-2c$

${:}\leadsto$ $\sf 5c+2c=56-28$

${:}\leadsto$ $\sf 7c=28$

${:}\leadsto$ $\sf c={\dfrac {28}{7}}$

${:}\leadsto$ $\sf c=4$

4 0

2 years ago

Read 2 more answers

The class-mark of the class 80-90 is​

The class-mark of the class 80-90 is