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baherus [9]
3 years ago
11

The time t (in minutes) for a small plane to climb to an altitude of h feet is given by t = 50 log10 (18000/(18000-h)) where 180

00 feet is the plane's absolute ceiling. a. Determine the domain of the function appropriate for the context of the problem. b. Graph the function and identify any asymptotes. c. As the plane approaches its absolute ceiling, what can be said about the time required to further increase its altitude. d. Find the amount of time it will take for the plane to climb to an altitude of 4000 feet.
Mathematics
1 answer:
Arlecino [84]3 years ago
5 0
Domain = x<18000(You cant og a negative number)
Am I actually supposed to graph it? enter the equation on desmos.com
It takes longer to make the same altitudinal gain
t=50log(18000/(18000-4000))=50log(18000/14000)=5.457
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Consider the following pair of equations: −x − y = −5 y = x + 1 If the two equations are graphed, at what point do the lines rep
Mnenie [13.5K]
-x - y = -5
y = x + 1

-x -(x + 1) = -5
-x - x - 1 = -5
-2x = -5 + 1
-2x = -4
x = -4/-2
x = 2

y = x + 1
y = 2 + 1
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6 0
3 years ago
Which is the value of this expression when m=3 and n=-5? (6m^-1 n^0)^-3
iragen [17]

Answer:

The answer is C.

Step-by-step explanation:

I would simplify the expression first.

Equation: (6m^-1)^-3

You can get rid of n^0 because that equals 1.

Any expression raised to the power of -1 equals its reciprocal.

Equation: (6/m)^-3

Equation: (m/6)^3

Final Equation: m^3/216

Now, plug in 3.

(3)^3/216.

27/216 = 1/8

Hope this helps!

6 0
3 years ago
What's the answer ?????
Tanzania [10]
The awnser is a I hope I helped you out
4 0
3 years ago
Read 2 more answers
Write $1,234.56 in words, as it would appear on a check.
aliya0001 [1]

Answer:

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3 0
3 years ago
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1. The county fair charges $1.50 per ticket for the rides. Jermaine bought 20 tickets for the rides and spent a total of $48.75
MAVERICK [17]

Answer: Our variable be z for fair admission and our required linear equation will be

\$1.50x+z=\$48.75

Explanation:

Since we have given that

Cost per ticket for the rides =$1.50

Total amount she spent = $48.75

Let the total cost be y

Let the number of ride tickets be x

<u>a) Define your variable:</u>

Let the amount spent on fair admission be z

<u>b) Write a linear equation that can be used to determine the cost for ride tickets and fair admission:</u>

Our required equation will be

\$1.50x+z=\$48.75

Here, number of ride tickets = 20

So,

20\times 1.50+z=48.75\\\\30+z=48.75\\\\z=48.75-30=18.75

So, the cost for fair admission = $18.75

7 0
3 years ago
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