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RUDIKE [14]
3 years ago
14

7:59 PM

Mathematics
1 answer:
ollegr [7]3 years ago
7 0

Answer:

hi friends how are you all about you my friend

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A sum has five addends. Each addend is a unit fraction. The sum is 1. What are the addends?
Bogdan [553]
I would assume 1/5 is your answer. As 1/5+1/5+1/5+1/5+1/5 = 5/5 which is 1.
4 0
3 years ago
Read 2 more answers
Plot and label all the points that are 4 units from point P AND that share the same x coordinate as point P. Write the coordinat
Lilit [14]
The answers should be: (-2,5), (-2,-2), (-6,-1), (2,1)





Hope this helped :)
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2 years ago
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Tamiku [17]
So the circle is 39.25
And the area of triangle 30 together about 39.25
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When is a protractor preferred to a ruler when finding a measurement
Keith_Richards [23]
When measuring an angle.
7 0
3 years ago
Answer the question in the picture
nekit [7.7K]

Recall the angle sum identities:

\sin(x+y)=\sin x\cos y+\cos x\sin y

\cos(x+y)=\cos x\cos y-\sin x\sin y

Now,

\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}

Divide through numerator and denominator by \cos x\cos y to get

\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

Next, we use the fact that x,y lie in the first quadrant to determine that

\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2

\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}

So we then have

\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1

Finally,

\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73

4 0
3 years ago
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