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Agata [3.3K]
3 years ago
9

Please help with this math

Mathematics
1 answer:
Luden [163]3 years ago
3 0
The first one
2 \times 3 \times 5
second one
2 \times5 + 3

third one
2 \times 3 - 5
last one
2 \times 3 + 5
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hi im 7th grade and i feel like people think i smell when i do everything to not smell. i wake up take a shower with soap aplly
mr_godi [17]

Answer:

Step-by-step explanation:

This might be a hygiene problem. What causes the unpleasant smell is the bacteria that build up on your sweaty skin and react with sweat and oils to grow and multiply when sweat reacts with bacteria on the skin. These bacteria break down proteins and fatty acids, causing body odor in the process. If deodorant isn’t good enough , I recommend perfume, the perfume smell lasts longer than deodorant I would think. But shower everyday, full clean down, but if ur hygiene is ok, I recommend going to the doctor for a checkup. Hopefully your problem will be resolved. Also use lotion.

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3 years ago
Graph a line with a slope of -5 that contains the
denis23 [38]

Answer:

Step-by-step explanation: idk

5 0
3 years ago
What is the volume of the cube below?
svlad2 [7]

Answer:

27

Step-by-step explanation:

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i dont know how to convert to whatever <em>h </em>is so this is the best answer i can give

3 0
2 years ago
Read 2 more answers
If n and k are positive integers, is n divisible by 6 ? (1) n = k(k + 1)(k – 1) (2) k – 1 is a multiple of 3.
xz_007 [3.2K]

Answer: yes, it is

Step-by-step explanation:

A number is divisible by 6 if it is divisible by 2 and 3 simultaniously.

n = k(k+1)(k-1)

If k-1 is a multiple of 3, n is divisible by 3, so one of the requirements is ok.

Now, if k-1 is a multiple of 3, it can be even or odd.

if k-1 is even, then it is divisible by 2 and as it is divisible by 3 as well, n is divisible by 6

if k-1 is odd, then k and k+1 is even, hence, divisible by 2.

As n = k(k+1)(k-1), n is also divisible by 6.

4 0
4 years ago
PLease help!!
weqwewe [10]
√45 + √125

= 3√5 + 5√5

= 8√5

Answer is C.

Hope it helps!
6 0
3 years ago
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