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Lorico [155]
2 years ago
10

Frankie wants to build a path from one corner of his yard to the opposite corner. his yard measures 20 ft. x 32 ft. what will be

the length of his path to the nearest tenth of a foot?
21.5 ft
25.0 ft
32.6 ft
37.7 ftfrankie wants to build a path from one corner of his yard to the opposite corner. his yard measures 20 ft. x 32 ft. what will be the length of his path to the nearest tenth of a foot?
21.5 ft
25.0 ft
32.6 ft
37.7 ft.
Mathematics
1 answer:
ira [324]2 years ago
5 0

The length of his path to the nearest tenth of a foot is 37.7 ft option fourth is correct.

<h3>What is the Pythagoras theorem?</h3>

The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.

We have:

Frankie wants to build a path from one corner of his yard to the opposite corner. his yard measures 20 ft. x 32 ft.

From the Pythagoras theorem:

Perpendicular(P) = 32 ft

Base(B) = 20 ft

H = √(32²+20²)

H = √1424

H = 37.7 ft

Thus, the length of his path to the nearest tenth of a foot is 37.7 ft option fourth is correct.

Learn more about Pythagoras' theorem here:

brainly.com/question/21511305

#SPJ1

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Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3>  P(h) =P_0e^{-0.00012h} </h3><h3> In this function P_o   is the air pressure at the surface of the earth, and h is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

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In order to calculate at what  height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute P(h)=0.5P_o into the function:

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Remember the following property of logarithms:

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Then, you get this result:

0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2

7 0
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Ik the answer but can you explain how <br> Giving brainliest
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Answer:

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hope that helps

Step-by-step explanation:

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