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2 years ago

Find the midpoint A and B where A has a coordinates (2, 7) and B has coordinates (6,3)

Mathematics

2 answers:

solong [7]2 years ago

7 0

Answer:

(2+6)/2= 4 (x-coordinate of midpoint)

(7+3)/2= 5(y=coordinate of midpoint)

ExtremeBDS [4]2 years ago

3 0

Answer:

Hope it will help you:)

Step-by-step explanation:

Solution:

here,

A(2,7)-( $x_{1,}y_{1$ )

B(6,3)-( $x_{2},y_{2$ )

Now using midpoint formula,

midpoint of ab=(x1 + x2)/2, (y1 + y2)/2

=(2+6)/2,(7+3)/2

=(8/2,10/2)

=(4,5)

The midpoint of AB is(4,5).

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3 years ago

100x+300y=1.200<br> (2/3x+10)/100=(y+20)/300

AlexFokin [52]

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3 years ago

Select the correct answer from each drop-down menu.

mr_godi [17]

Answer:

correct option for first blank is 5/4 and for second blank is $\frac{ 3i\sqrt{7}}{4}$

i.e m= $\frac{5}{4}\pm\frac{ 3i\sqrt{7}}{4}$

Step-by-step explanation:

The given equation

$m^2 - \frac {5m}{2} = \frac{-11}{2}$

and we have to find m= ______ ± ________

We can use quadratic formula to solve this question.

The above equation can be written as: $m^2 - \frac {5m}{2} + \frac{11}{2} = 0$

and the formula used will be:

$m= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Putting values of a= 1, b= -5/2 and c= 11/2 and solving we get: $m=\frac{-\frac{-5}{2}\pm\sqrt{{(\frac{-5}{2})}^2-4(1)(\frac{11}{2})}}{2(1)}\\\\m=\frac{\frac{5}{2}\pm\sqrt{(\frac{25}{4})-22}}{2}\\m=\frac{\frac{5}{2}\pm\sqrt{(\frac{-63}{4})}}{2}\\m= \frac{\frac{5}{2}}{2}\pm\frac{\sqrt{(\frac{-63}{4})}}{2}\\m= \frac{5}{4}\pm\frac{\sqrt{-63}}{4}$

Since there is - sign inside the √ so $\sqrt{-1}$ is equal to i and we have to divide $\sqrt{63}$ into its multiples such that the square root of one multiple is whole no so,

$\sqrt{63}$ = $\sqrt{9}* \sqrt{7}$ = $3* \sqrt{7}$

Putting value of $\sqrt{63}$ and $\sqrt{-1}$

the value of m= $\frac{5}{4}\pm\frac{ 3i\sqrt{7}}{4}$

so, correct option for first blank is 5/4 and for second blank is $\frac{ 3i\sqrt{7}}{4}$ .

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3 years ago

A car is purchased for $28,000. After each year, the resale value decreases by

Dennis_Churaev [7]

$\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=I(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &28000\\
r=rate\to 35\%\to \frac{35}{100}\to &0.35\\
t=\textit{elapsed time}\to &3\\
\end{cases}
\\\\\\
A=28000(1-0.35)^3\implies A=28000(0.65)^3\implies A=7689.5
\\\\\\
\textit{which rounds up to }7689$

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3 years ago

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Read 2 more answers

Find the midpoint A and B where A has a coordinates (2, 7) and B has coordinates (6,3)​

Find the midpoint A and B where A has a coordinates (2, 7) and B has coordinates (6,3)