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Nataliya [291]
2 years ago
5

What is 5+5 Someone plzzz help me Sike

Mathematics
1 answer:
horrorfan [7]2 years ago
6 0

Answer:

is that dababy?

Step-by-step explanation:

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The value of yvaries directly with x. If x= 3, then y= 21.<br> What is the value of x when y= 105?
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If y = 105, x should be 15: x =15

Step-by-step explanation:

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There are 26.2 miles in a marathor write the number of miles using a fraction
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26 and 2/10 is how to write the answer as a mixed number fraction.
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Use the distributive property to express 28+42
vovikov84 [41]
To express the sum of two numbers using distributive property, we factor out the highest common factor (HCF) of the two numbers (i.e. the greatest number that can divide the two numbers without remainder)

28 = 2 x 2 x 7
42 = 2 x 3 x 7

The HCF of 28 and 42 is given by 2 x 7 = 14

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3 years ago
Fill the gaps 9,16, ,36,49,
WITCHER [35]
9, 16, __, 36, 49, ___

16 - 9 = 7

49 - 36 = 13

13 - 7 = 6

6 + 7 = 13 

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SO, 9, 16, 23, 36, 49, 56

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7 0
3 years ago
Read 2 more answers
The volume of a spherical cancerous tumor is given by the following equation. V(r) =(4/3)pi r^3 If the radius of a tumor is esti
Dimas [21]

Answer:

The error that might occur is \±0.123cm^3

Step-by-step explanation:

Given

V = \frac{4}{3}\pi r^3

Radius,\ r = 1.4cm

Error = 0.005cm

Required

Determine the error that might occur in the volume of the tumor

Given that there's an error in measurement, this question will be solved using the concept of differentiation;

First, we'll rewrite the given parameters in differentiation notations;

r = 1.4 --- Radius

dV = \±0.005 --- Change in measurement

V(r) = \frac{4}{3}\pi r^3 --- Volume as a function of radius

The relationship between the above parameters is as follows;

\frac{dV}{dr} = V'(r)

This can be rewritten as

\frac{dV}{dr} = (V(r))'

Substitute \frac{4}{3}\pi r^3 for V(r)

\frac{dV}{dr} = (\frac{4}{3}\pi r^3)'

Multiply both sides by dr

dr * \frac{dV}{dr} = (\frac{4}{3}\pi r^3)' * dr

dV = (\frac{4}{3}\pi r^3)' * dr

dV = \frac{4}{3}\pi( r^3)'  dr

Differentiate

dV = \frac{4}{3}\pi( r^3)'  dr

dV = \frac{4}{3}\pi* 3r^2\  dr

dV = 4\pi* r^2\  dr

Substitute the values of r, dr and take \pi as 3.142

dV = 4 * 3.142* 1.4^2 * \±0.005

dV = \±0.1231664

dV = \±0.123 <em>(Approximated)</em>

Hence, the error that might occur is ±0.123

6 0
3 years ago
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