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3 years ago

15

A forest covers 72,000 acres. A survey finds that 0.7% of the forest is old-growth trees. How many acres of old-growth trees

are there?

1 answer:

Vsevolod [243]3 years ago

6 0

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When a person purchases stock in a company, he is in reality loaning money to the company. True False

Alik [6]

I think it is False

God Bless

4 0

3 years ago

Read 2 more answers

(SUPER EASY) ILL GIVE BRAINLIEST TOO. <br><br><br> just answer all the questions you know.

wolverine [178]

Answer:

what is the question

Step-by-step explanation:

5 0

2 years ago

Sort the ratios listed at the right into bins so that equivalent ratios are grouped together:

cestrela7 [59]

Step $1$

<u>Find the irreducible fraction in each ratio</u>

<u>case 1)</u> $\frac{40}{64}$

Divide by $8$ boths numerator and denominator

$\frac{40}{64}=\frac{5}{8}$

<u>case 2)</u> $\frac{5}{75}$

Divide by $5$ boths numerator and denominator

$\frac{5}{75}=\frac{1}{15}$

<u>case 3)</u> $\frac{14}{35}$

Divide by $7$ boths numerator and denominator

$\frac{14}{35}=\frac{2}{5}$

<u>case 4)</u> $\frac{24}{64}$

Divide by $8$ boths numerator and denominator

$\frac{24}{64}=\frac{3}{8}$

<u>case 5)</u> $\frac{6}{15}$

Divide by $3$ boths numerator and denominator

$\frac{6}{15}=\frac{2}{5}$

<u>case 6)</u> $\frac{65}{104}$

Divide by $13$ boths numerator and denominator

$\frac{65}{104}=\frac{5}{8}$

<u>case 7)</u> $\frac{66}{176}$

Divide by $22$ boths numerator and denominator

$\frac{66}{176}=\frac{3}{8}$

<u>case 8)</u> $\frac{12}{30}$

Divide by $6$ boths numerator and denominator

$\frac{12}{30}=\frac{2}{5}$

<u>case 9)</u> $\frac{15}{225}$

Divide by $15$ boths numerator and denominator

$\frac{15}{225}=\frac{1}{15}$

<u>case 10)</u> $\frac{6}{16}$

Divide by $2$ boths numerator and denominator

$\frac{6}{16}=\frac{3}{8}$

<u>case 11)</u> $\frac{15}{24}$

Divide by $3$ boths numerator and denominator

$\frac{15}{24}=\frac{5}{8}$

<u>case 12)</u> $\frac{48}{128}$

Divide by $16$ boths numerator and denominator

$\frac{48}{128}=\frac{3}{8}$

Step $2$

<u>Sort the ratios into bins</u>

1<u>) First Bin</u>

<u> $Ratio=\frac{5}{8}$ </u>

$\frac{40}{64}$

$\frac{65}{104}$

$\frac{15}{24}$

<u>2) Second Bin </u>

<u> $Ratio=\frac{1}{15}$ </u>

$\frac{5}{75}$

$\frac{15}{225}$

<u>3) Third Bin</u>

$Ratio=\frac{2}{5}$

$\frac{14}{35}$

$\frac{6}{15}$

$\frac{12}{30}$

4<u>) Fourth Bin</u>

<u> $Ratio=\frac{3}{8}$ </u>

$\frac{24}{64}$

$\frac{66}{176}$

$\frac{6}{16}$

$\frac{48}{128}$

3 0

3 years ago

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Whats (c-7)(c+5) , (double brackets)

kherson [118]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

let's evaluate :

$(c - 7)(c + 5)$

${c}^{2} + 5c - 7c - 35$

${c}^{2} - 2c - 35$

6 0

2 years ago

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What's one of the factors of x² - x – 6 ?

mr Goodwill [35]

$x^2-x-6=x^2+2x-3x-6=x(x+2)-3(x+2)\\\\=\boxed{(x+2)(x-3)}$

The factors are: (x+2) and (x-3).

$x^2-x-6=x^2+\underbrace{2x-3x}_{=-x}-6\\\\=\underbrace{x\cdot\boxed{x}}_{=x^2}+\underbrace{2\cdot\boxed{x}}_{=2x}+\underbrace{\fbox{-3}\cdot x}_{=-3x}+\underbrace{\fbox{-3}\cdot2}_{=-6}=\boxed{x}(x+2)+\fbox{-3}(x+2)\\\\=(x+2)(x+(-3))=\boxed{(x+2)(x-3)}$

8 0

3 years ago