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2 years ago

Which inequality represents this sentence?

Mathematics

2 answers:

NikAS [45]2 years ago

7 0

Answer:

the first one due to the way up math works

LUCKY_DIMON [66]2 years ago

3 0

The first one
Since 5+4<10+2
And that’s trues
9<12

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Find the zeros of the polynomial function and state the multiplicity of each.

zheka24 [161]

$\bf f(x) = 4(x + 7)^2(x - 7)^3\implies 0 = 4(x + 7)^2(x - 7)^3
\\\\\\
0=(x+7)^2(x-7)^3\implies 
\begin{cases}
0=(x+7)^7\\
\qquad 0=(x+7)(x+7)\\
\qquad -7=x\\
\qquad -7=x\\
----------\\
0=(x-7)^3\\
\qquad 0=(x-7)(x-7)(x-7)\\
\qquad 7=x\\
\qquad 7=x\\
\qquad 7=x
\end{cases}$

the -7 is found there twice, so it has a multiplicity of 2
the +7 is there thrice, so it has multiplicity of 3

7 0

2 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

2 years ago

Solve the inequalities 3x2 – 11x > 20

Bas_tet [7]

Answer:

x=-10

Step-by-step explanation:

3x · 3x=9x-11x>20

-2x>20

÷-2 -2

___________-

x=-10

Hope this helps ∞

5 0

2 years ago

If you add 21 to my number and then multiply the result by 3, you will get 84 more than two-thirds of my number. Find my number.

Ksivusya [100]

Based on the calculations, the unknown number is equal to $\frac{-45}{7}$

Let the unknown number be x.

<h3>How to find an unknown number:</h3>

Translate the word problem into an algebraic expression, we have;

Adding 21 to the unknown number:

$21 +x$

Multiplying the result by 3:

$3\times (21+x)$

84 more than two-thirds of the unknown number:

$\frac{2x}{3} +84$

Equating the equations, we have:

$3\times (21+x) = \frac{2x}{3} +84\\\\43+3x=\frac{2x}{3} +84$

Cross-multiplying, we have:

$43+3x=\frac{2x}{3} +84\\\\129+9x=2x+84\\\\9x-2x=84-129\\\\7x=-45\\\\x=\frac{-45}{7}$

Read more on word problems here: brainly.com/question/13170908

5 0

2 years ago

Select all of the following ordered pairs that are in the solution set of the inequality shown.

Irina-Kira [14]

Answer:

points on the boundary line: (0, 10), (20, 0)
solution points not on the boundary line: (100, 100)

Step-by-step explanation:

We cannot tell from the posted picture whether the boundary line is solid or dashed, so the answer above is split into two parts. If the boundary line is solid (x+2y≥20), all three listed points are in the solution set. If the boundary line is dashed (x+2y>20), only (100, 100) is in the solution set.

8 0

3 years ago

Read 2 more answers