See the attached figure
radius of the circle = r = 6
the length of one side of the equilateral triangle = L
the height if the triangle = h
The shaded area is the required area.
∴The area = (1/3) (area of circle - area of triangle )
area of circle = π r² = π * 6² = 36 π
An equilateral triangle is inscribed in a circle of radius r
∴ The length of one side of the triangle = √3 * r
= 6√3
and the height of the triangle = (√3 /2) * 6√3 = 9
∴ Area of the triangle = 0.5 * 9 * 6√3 = 27√3
The required area = (1/3) (area of circle - area of triangle )
= (1/3) * ( 36π - 27√3 )
= 12π - 9√3
Instead of putting the diving put the multiply and you’re answer will be correct
Slope is three and the y intercept is four
C because the <span>interquartile range is the number in the middle but ther is no middle so what is between 70 and 80 it is 75</span>
Answer:
Distribute the 6 to the terms inside the parentheses.
5=6q-30-19
Combine like terms.
5=6q-49
Add 49 to both sides.
54=6q
Divide both sides by 6.
q=9
:)