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sleet_krkn [62]
2 years ago
13

What is The Value Of X

Mathematics
1 answer:
miss Akunina [59]2 years ago
5 0

Answer:

X = 92 degrees

Step-by-step explanation:

the angles of a triangle all add up to 180 degrees, so 40 plus 180-132 = 88

180-88= 92 so X = 92

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50 POINTS PLEASE HELP!!!! THIS. IS. URGENT. WILL GIVE BRAINLIEST PLEASE JUST GIVE A GOOD EXPLANATION/BREAKDOWN
Licemer1 [7]
  • Answer:\beta \beta \beta \beta \beta \beta \beta\frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} x^{2} x^{2} x^{2} \alpha \alpha

Step-by-step explanation:

4 0
1 year ago
A house purchased for $216,500 gains 2% of its value every year. If this growth rate continues, in how many years will the house
NikAS [45]

Answer: 36 years

Step-by-step explanation:

You can use the Rule of 72 to calculate how long it might take the house to double in value.

The Rule of 72 works by dividing 72 by the interest rate as a whole number and the result will be a rough estimate of the time in years it will take for the investment to double in size:

= 72 / 2

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3 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
3 years ago
In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t
Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

(Y_1)^2 and (Y_2)^2 have x^2 distribution with 1 degree of freedom

and V=(Y_1^2)+(Y_2)^2 has x^2 with 2 degree of freedom

F_v(v)=\frac{e^{-\frac{v}{2}}}2

Since we have to find the density formula

U=\sqrt{V}

We use method of transformation

h(V)=\sqrt{U}\\\\=U

There inverse function is h^-^1(U)=U^2

We derivate the fuction above with respect to u

\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u

Therefore,

F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U

8 0
3 years ago
(79,35+7,32) × 42,2-9543​
vladimir2022 [97]

Answer:

42(79,42,32)

Step-by-step explanation:

I got the solution by using  the  Trigonometric Identities. If somebody else could do a step by step explanation that would be great.  

3 0
3 years ago
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