Answer:
<em>Equation of line; y = - 6x</em>
Step-by-step explanation:
As we can see from this graph, point ( 0, 0 ) lying on this graph intersects the y - axis such that it forms a y - intercept of 0;
At the same time we can note that the change in y / change in x, in other words the slope, differs by a rise of 6 / run of - 1, 6 / - 1 being a slope of - 6;
If this equation is in slope - intercept form ⇒
y = a * x + b, where a ⇒ slope, and b ⇒ y - intercept,
<em>Equation of line; y = - 6x</em>
If m<2 is 18 then m<1 is 72
Answer:
Step-by-step explanation:
x +3 I x⁴ + 0x³ - 6x² + 0x -28 I x³ - 3x² + 3x - 9
x⁴ + 3x³
<u>- - </u>
-3x³ - 6x²
-3x³ - 9x²
<u> + + </u>
3x² + 0x
3x² + 9x
<u> - - </u>
-9x -28
-9x - 27
<u> + + </u>
-1
P(x) =(x +3)* (x³ - 3x² + 3x - 9) + (-1)
Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
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Answer:
5th term: -10
Step-by-step explanation:
To find the nth term in the sequence, you can substitute n into the equation:
d(n) = 6 - 4(n - 1)
Since we want the 5th term, we substitute 5:
d(5) = 6 - 4(5 - 1)
d(5) = 6 - 4(4)
d(5) = 6 - 16
d(5) = -10
