B would be your best answer looking at the graphic chart
Going off the idea that this is 4/(y+2) - 9/(y-2) = 9/(y^2-4), let's first rewrite y^2-4 in the form of a^2-b^2, where a=y and b=2.
y/(y+2)-9/(y-2)=9/(y^2-2^2)
Now, use difference of squares: a^2-b^2=(a+b)(a-b)
4/(y+2)-9/(y-2)=9/((y+2)(y-2))
Multiply both sides by the Least Common Denominator: (y+2)(y-2)
4(y-2)-9(y+2)=9
Then keep on simplifying until you get your answer
-5y-26=9
-5y=9+26
-5y=35
y=35/-5
y=-7
Yay! Our answer is y=-7!
Answer: Number of ways 
Step-by-step explanation:
When there is no replacement , we use combination to find the number of ways to choose things.
Number of ways to choose r things out of ( with out replacement) = 
The number of ways to choose 8 things = ![^8C_8=\dfrac{8!}{8!(8-8)!}=\dfrac{1}{0!}=1 [\because 0!=1]](https://tex.z-dn.net/?f=%5E8C_8%3D%5Cdfrac%7B8%21%7D%7B8%21%288-8%29%21%7D%3D%5Cdfrac%7B1%7D%7B0%21%7D%3D1%20%20%5B%5Cbecause%200%21%3D1%5D)
Hence, Number of ways
Since they reduced the markup price, or higher price, by 10%, the new markup price is 20% over the manufacturer price.
If you mean "factor over the rational numbers", then this cannot be factored.
Here's why:
The given expression is in the form ax^2+bx+c. We have
a = 3
b = 19
c = 15
Computing the discriminant gives us
d = b^2 - 4ac
d = 19^2 - 4*3*15
d = 181
Note how this discriminant d value is not a perfect square
This directly leads to the original expression not factorable
We can say that the quadratic is prime
If you were to use the quadratic formula, then you should find that the equation 3x^2+19x+15 = 0 leads to two different roots such that each root is not a rational number. This is another path to show that the original quadratic cannot be factored over the rational numbers.
