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irakobra [83]
2 years ago
10

30 POINTS JUST ANSWER

Mathematics
1 answer:
SSSSS [86.1K]2 years ago
7 0

The slope of line AB, BC, CD and AD are 1, -1/6, 2, -4/6 respectively. Quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C

<h3>How to determine the slope</h3>

Formula for slope is given as;

Slope = \frac{y2 -y1}{x2 -x1}

A(-4 -1)

B(-1 2)

C(5 1)

D(1 -3)

a. Slope of line AB = \frac{2- (-1)}{-1 (-4)} = \frac{2+ 1}{-1 + 4} = \frac{3}{3} = 1

b. Slope of line BC = \frac{1-2}{5-(-1)} = \frac{-1}{6}

c. Slope of line CD = \frac{-3 - 5}{1-5} = \frac{-8}{-4} = 2

d. Slope of line AD = \frac{-3 (-1)}{1 -(-4)} = \frac{-4}{5}

Quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C

Thus, the slope of line AB, BC, CD and AD are 1, -1/6, 2, -4/6 respectively.

and quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C

Learn more about a parallelogram here:

brainly.com/question/3050890

#SPJ1

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