The solution to the compound inequality given as 6b < 36 or 2b + 12 > 6 is b < 6 or b > -3
<h3>How to solve the
compound inequality?</h3>
The compound inequality is given as:
6b < 36 or 2b + 12 > 6
Evaluate the like terms in the individual inequalities
6b < 36 or 2b > -6
Divide the individual inequalities by the coefficients of b
b < 6 or b > -3
Hence, the solution to the compound inequality given as 6b < 36 or 2b + 12 > 6 is b < 6 or b > -3
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The answer:
the main rules of the use of logarithm are
loga[a] = 1
loga[AxB] =loga[A] +loga[B] for all value positive of A and B
loga[A/B] = loga[A] - loga[B] for all value positive of A and B
in our case, <span>log8 4a (b-4/c4)
so it is equivalent to </span>log8 4a + <span>log8(b-4/c4)
and since </span>loga[A/B] = loga[A] l - oga[B] , log8(b-4/c4) =log8(b-4) - log8(c4)
the possible expression:
log8 4a (b-4/c4) = log8 4a + log8(b-4) - log8(c4)
Answer:
n/3 - 18
Step-by-step explanation:
"quotient of a number and 3" is n/3, and so
"18 less than the quotient of a number and 3" as an expression is:
n/3 - 18
Volume of a cube is s³
Total surface Area of a cube is 6s².
Therefore, given a volume of 27cm³
s³=27,
s=3√27
s=3cm.
Total surface Area
A=6s²
A=6×(3×3)
A=6×9
A=54cm².
Answer:
1000
Step-by-step explanation:
To solve this you divide 10/0.01 and you get 1000.
Hope it helps!
