Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
Answer:
20x-12
Step-by-step explanation:
Given:
7(3x−1)−(x+5)
Step 1: Distribute the Negative Sign:
=7(3x−1)+−1(x+5)
=7(3x−1)+−1x+(−1)(5)
=7(3x−1)+−x+−5
Step 2: Distribute:
=(7)(3x)+(7)(−1)+−x+−5
=21x+−7+−x+−5
Step 3: Combine
=21x+−7+−x+−5
=(21x+−x)+(−7+−5)
=20x+−12
Answer:
55%
Step-by-step explanation:
Out of 100 blocks 55 are shaded
so the fraction would be 55/100
55/100 = 55%
