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Lostsunrise [7]
2 years ago
12

Suppose that prices of recently sold homes in one neighborhood have a mean of $220,000 with a standard deviation of $7450. Using

Chebyshev's Theorem, what is the minimum percentage of recently sold homes with prices between $197,650 and $242,350? Round your answer to one decimal place.
Mathematics
1 answer:
GenaCL600 [577]2 years ago
5 0

The minimum percentage of recently sold homes with prices between $197,650 and $242,350 is 88.9%.

<h3>What is Mean ?</h3>

Mean is the ratio of the sum of all the data points to the number of data points.

It is given that

mean of $220,000 with a standard deviation of $7450.

The range is given , let the range is represented by x - --y

It is given that x = 197650 and y = 242350

Let the number of homes sold is k

To determine the value of k

upper level = (y-mean)/standard deviation = (242350-220000)/7450 = 3

lower level = (mean-x)/standard deviation = (220000-197650)/7450 = 3

probability = 1-(1/k²)

k= 3

= 1 - (1/3^2)

= 1 - 1/9

= 0.889 or 88.9%

So, the minimum percentage of recently sold homes with prices between $197,650 and $242,350 is 88.9%.

To know more about Mean

brainly.com/question/521501

#SPJ1

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  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

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We are given –

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\qquad⇢ Height of cylinder, h = 8 inches.

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Formula to find the surface cylinder given by –

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\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

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