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blsea [12.9K]
2 years ago
14

The volume of a gas is inversely proportional to the pressure of a gas is known as:.

Chemistry
1 answer:
bazaltina [42]2 years ago
7 0

Answer:

Boyle's law states this.

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What happens to energy when frequency
Law Incorporation [45]

Answer:

Energy is halved.

Explanation:

Energy and Frequency are directly proportional. If frequency decreases, energy increases. If frequency increases, energy increases. If frequency is halved, energy is also halved.

8 0
3 years ago
If two atoms are bonded to a central atom with no lone pairs , how will they be arranged?
Dmitriy789 [7]
Most likely the geometric form of the molecule will be linear.
Explanation:
One possibility is the central atom being an atom with two valance electrons. This will create a liner molecule with no lone pairs of electrons
Another possibility is a central atom being an atom with four valance electrons. If the two atoms each require two bonds like oxygen the result will be a linear molecule with no lone pairs of electrons.
3 0
3 years ago
How do you mesure 25.0 milliliters of water(volume)
andreyandreev [35.5K]

This measurement converter chart will help you figure out the liquid measurements called for.

0.5 ml = ⅛ teaspoon.

1 ml = ¼ teaspoon.

2 ml = ½ teaspoon.

5 ml = 1 teaspoon.

15 ml = 1 tablespoon.

25 ml = 2 tablespoons.

50 ml = 2 fluid ounces = ¼ cup.

75 ml = 3 fluid ounces = ⅓ cup.

6 0
3 years ago
A 26-week-old baby was brought to the pediatric clinic because of increasing lethargy and cyanosis. The infant has been in good
Elena-2011 [213]

Answer:

what i think is that,hemoglobin is what makes the blood red and the methemoglobin is what

Explanation:

3 0
3 years ago
Octane has a density of 0.692 g/ml at 20oc. how many grams of o2 are required to burn 15.0 gal of c8h18 (the average capacity of
Hatshy [7]

Octane has a density of 0.692 g/ml at 20°C. Grams of O₂ required to burn 15.0 gal of C₈H₁₈ is 1.37868×10⁵g.

Octane is a hydrocarbon having eight carbon atoms and have single bonds only.

Given,

Density of octane = 0.692g/ml

Temperature = 20°C = 293K

Amount of Octane present = 15gal

Molar mass of octane = 114g

We know that,

1 gal = 3.78541L = 3785.4ml

Hence, 15 gal = 56781 ml

Now let's calculate the Mass of octane required:

Mass of octane = 0.692 x 56781

Mass of octane = 39292.45 g

According to the given equation,

C₈H₁₈ + 12.5O₂ ---------> 8CO₂ + 9H₂O

Also, 114g of octane needs-------> 400g of oxygen

39292.45g of octane needs ---------> 137868.24g of oxygen

Hence, oxygen needed to burn octane is 1.37868×10⁵g

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

4 0
2 years ago
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