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3 years ago

The city is using sand trucks to place on the road during ice conditions which best explians the use of the sand

1 answer:

6 0

The sand provides a rough surface on top of the ice for the cars' tires to grip onto. It provides more friction. Salt melts the ice and often provides more friction (the disadvantage is that it eats concrete!).

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What is the percent-by-mass, %(m/m), concentration of sucrose ( table sugar) in a solution made by dissolving 22.8 g of sucrose

Ede4ka [16]

Answer:

32.6 %

Explanation:

Given data

Mass of sucrose (solute): 22.8 grams

Mass of water (solvent): 47.1 grams

Step 1: Calculate the mass of the solution

The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.

m(solution) = m(solute) + m(solvent)

m(solution) = 22.8 g + 47.1 g

m(solution) = 69.9 g

Step 2: Calculate the percent-by-mass of sucrose in the solution

We will use the following expression.

$\% m/m = \frac{mass\ of\ sucrose}{mass\ of\ solution} \times 100\% = \frac{22.8g}{69.9g} \times 100\% = 32.6 \%$

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3 years ago

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Please answer the question that is attached to this question. It will be a BIG help for my homework if you give a proper explana

vichka [17]

Naw man I ain’t the correct answer

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2 years ago

Explain how following a fitness plan can help you meet a goal

vodka [1.7K]

Because if you follow a fitness plan you can get done a lot of stuff that you can't without a plan so like you make a plan of what you are going to do instead of just doing random fitness stuff

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3 years ago

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SPACE SCIENCE If the Milky Way galaxy were a pizza, would the Earth be in the cheese or on the crust? Justify your answer.

AURORKA [14]

Answer:

Crust

Explanation:

we are part of one of the arms of the galaxies mostly because the centre is way to dense

7 0

3 years ago

Unknown element has two isotopes. Isotope A has a mass of 34 amu and abundance of 52%, isotope B has a mass of 33 amu and abunda

ZanzabumX [31]

Answer:

x = 33.52 amu

Explanation:

It is given that,

Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.

Let x is the average atomic mass of this element. It can be calculated as follows :

$x=52\%\ \text{of}\ 34+48\%\ \text{of}\ 33\\\\x=\dfrac{52}{100}\times 34+\dfrac{48}{100}\times 33\\\\x=0.52\times 34+0.48\times 33\\\\x=33.52\ \text{amu}$

So, the average atomic mass of this element is 33.52 amu.

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3 years ago