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Art [367]
2 years ago
12

The density of NO2 in a 4.50 L tank at 760.0 torr and 25.0 °C is ________ g/l.

Chemistry
1 answer:
Sonbull [250]2 years ago
4 0

The answer is c-1.68

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1pt Which is an example of an alloy?<br> O A. steel<br> OB. salt water<br> O C. air<br> O D. iron
77julia77 [94]
Steel? Hope this helps?

4 0
2 years ago
5.80 gg of NaCl in 350. mL of a NaClsolution
Delicious77 [7]

Answer:

Solution is 0.28 M

You can also say, [NaCl] = 0.28 mol/L

Explanation:

As you have a solute mass and the solution's volume, you may find the molarity concentration of solution.

Molarity specifies the moles of solute in 1 L of solution

We convert the volume of solution to L → 350 mL . 1L / 1000 mL = 0.350L

We convert the mass of solute to moles → 5.80 g . 1mol / 58.45 g = 0.0992 moles

Molarity (mol/L) = 0.0992 mol /0.350L = 0.28M

6 0
2 years ago
Which of the following statement(s) about chemical bonding
spin [16.1K]

Answer:B

Explanation:

6 0
2 years ago
Why would the white blood cells have an abundance of lysosomes?
77julia77 [94]

Answer:

Explanation:

A. White blood cells have many lysosomes because they need to produce a lot of glucose and oxygen.

Lysosomes are found in all animal cells, but are most numerous in disease-fighting cells, such as white blood cells. This is because white blood cells must digest more material than most other types of cells in their quest to battle bacteria, viruses, and other foreign intruders.

6 0
3 years ago
Read 2 more answers
A 98.0°C piece of cadmium (c=.850J/g°C) is placed in 150.0g of 37.0°C water. After sitting for a few minutes, both have a temper
Eduardwww [97]
The answer is 19.9 grams cadmium. 
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
     heat lost by cadmium = heat gained by the water
     -qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
     -qcadmium = qwater
     -(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
     mcadmium = 19.9 grams
3 0
2 years ago
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