<u>Answer:</u> The molar composition of nitrogen gas is 0.6 and that of oxygen gas is 0.4
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
Given mass of nitrogen gas = 51.3 mg = 0.0513 g (Conversion factor: 1 g = 1000 mg)
Molar mass of nitrogen gas = 28 g/mol
Volume of solution = 2 L
Putting values in above equation, we get:
To calculate the partial pressure, we use the equation given by Henry's law, which is:
where,
= Henry's constant =
= molar solubility of nitrogen gas =
Putting values in above equation, we get:
We are given:
Total pressure of the mixture = 2.50 atm
Partial pressure of oxygen gas = 2.50 - 1.50 = 1.00 atm
To calculate the mole fraction of a substance at 25°C, we use the equation given by Raoult's law, which is:
......(1)
where,
= partial pressure
= total pressure
= mole fraction
We are given:
Putting values in equation 1, we get:
We are given:
Putting values in equation 1, we get:
Hence, the molar composition of nitrogen gas is 0.6 and that of oxygen gas is 0.4