Answer:
B
Explanation:
hope it helpls plz name brainlest
I don’t have a picture but I can describe it to you.
The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.
The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.
Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.
Hope this helps!
Answer:
C2H4O2 + 2O2 —> 2CO2 + 2H20
The coefficients are 1, 2, 2, 2
Explanation:
C2H4O2 + O2 —> CO2 + H20
To balance the above, do the following
Since there are 2 carbon on the left, put 2 in front of CO2, we have
C2H4O2 + O2 —> 2CO2 + H20
We have 4 hydrogen on the left, to balance it put 2 in front of H2O i.e
C2H4O2 + O2 —> 2CO2 + 2H20
Now, we have a total of 6 oxygen on the right side. To balance it, put 2 in front of O2:
C2H4O2 + 2O2 —> 2CO2 + 2H20
The coefficients are 1, 2, 2, 2
<h3><u>Answer;</u></h3>
= 3.12 moles of NaNO3
<h3><u>Explanation</u>;</h3>
The equation for the reaction is;
Pb(NO3)2+Na2CrO4 → PbCrO4+2NaNO3
Molar ratios in the reaction are ; 1 : 1 : 1 : 2
Which means; One mole of (Na2CrO4) produces two moles of (NaNO3)
We can calculate the number of moles of Na2CrO4,
Moles (na2CrO4) = 253g /162
= 1.56 moles
Moles of NaNO3 will be;
= 1.56 moles x 2 = 3.12 moles
Therefore, the moles of NaNO3 that will be produced will be 3.12 moles
If the ion is a cation, it has a positive charge because it LOST electrons. If its an anion, then it has a negative electron because it GAINED electrons.
