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3 years ago

Which of the following values of x is NOT a solution to the following inequality?

Mathematics

1 answer:

vova2212 [387]3 years ago

8 0

Answer:

A. 1

Step-by-step explanation: You have to substitute the numbers in for x

A. 1:

-5x -1 < -9

-5(1) - 1 < -9

-5 - 1 < -9

-6 < -9

B. 2:

-5x - 1 < -9

-5(2) - 1 < -9

-10 - 1 < -9

-11 < -9

C. 3:

-5x - 1 < -9

-5(3) - 1 < - 9

-15 - 1 < -9

-16 < -9

D. 4:

-5x - 1 < -9

-5(4) - 1 < -9

-20 - 1 < -9

-21 < -9

Remember, a negative plus another negative is a negative

Hope this helps you!!! :)

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3(x-2) < 2(x+9)<br><br> 1. x<12<br> 2.x>12<br> 3. x<24<br> 4.x>24

Nataly_w [17]

Answer:

3rd option x<24

Step-by-step explanation:

3×(x-2)<2×(x+9)

3 times everything in the bracket and 2 times everything in the bracket.

3x(-2x)-6<2x(-2x)+18 take away 2x from both sides

( Opposite operators EG, Add becomes subtract)

x-6(+6)<18(+6) add 6 on both sides

x<24

7 0

3 years ago

Find the values of the variables.

8_murik_8 [283]

Answer:

x = 16 y = 22.627 (or 16 $\sqrt{2$ )

Step-by-step explanation:

cos(45) = 16/y

y = 16/cos(45)

y = 22.627

tan(45) = 16/x

x = 16/tan(45)

x = 16

*this can also be found because we know this is a right triangle with two angles of 45 degrees. This means that both sides will be equal so x will be 16 and the diagonal will be 16 root 2 (22.627)

5 0

3 years ago

What are the measures of ∠1, ∠2, and ∠3? Enter your answers in the boxes.

GarryVolchara [31]

Answer: m<1 is 60, m<2 is 60, and m<3 is 120

Step-by-step explanation:

M<1 is 60 and m<2 is also 60 because the interior triangle angles have to equal 180 so M<1 + m<2 + 60 = 180 so m<1 and m<2 are both sixty.

m<3 is 120 because m<2 and m<3 are supplementary so if a supplementary angle is equal to 180 then m<2 + m<3 = 180 and m<2 is 60 so m<3 is 120.

3 0

3 years ago

Answer the following questions.

schepotkina [342]

<h3><u>Answer the following questions :-</u></h3>

Raja is junk seller. He sells many things. Here is given the list of junk.

Check the Raja's rate list and solve the following questions.

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind \: of\:junk} & \bf{Price \: of \: 1 \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \: Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

<h2><u>Solutions :-</u></h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: newspaper = Rs.5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 20 \: kg \: newspaper = Rs.20 \times 5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 20 \: kg \: newspaper = Rs.100}}}$

$\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost \: of \: 20 \: kg \: newspaper = Rs.100}}}}}}$

<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

$\rule{200}{1.5}$

2. What is the cost of 5 kg Iron?

$\quad{\longrightarrow{\sf{Cost\: of \: 1 \: kg \: iron = Rs.10}}}$

$\quad{\longrightarrow{\sf{Cost\: of \: 5 \: kg \: iron = Rs.10 \times 5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 5 \: kg \: iron = Rs.50}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost \: of \: 5 \: kg \: iron = Rs.50}}}}}$

<u>∴ The cost of 5 kg iron is Rs.50.</u>

$\rule{200}{1.5}$

3. What is the cost of 9 kg Plastic?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: plastic = Rs.8}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 9 \: kg \: plastic = Rs.8 \times 9}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 9 \: kg \: plastic = Rs.72}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \: 9 \: kg \: plastic = Rs.72}}}}}$

<u>∴ The cost of 9 kg plastic is Rs.72. </u>

$\rule{200}{1.5}$

4. What is the cost of 7 kg Brass?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: brass = Rs.50}}}$

$\quad{\longrightarrow{\sf{Cost\: of \: 7 \: kg \: brass = Rs.50 \times 7}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 7 \: kg \: brass = Rs.350}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost \: of \: 5 \: kg \: brass = Rs.350}}}}}$

<u>∴ The cost of 7kg brass is Rs.350.</u>

$\underline{\rule{200pt}{2pt}}$

7 0

2 years ago

Alica had 10/12 of fabric she used 8/12 for a pillow how much fabric dod she have left? Explain how you found your answer .

Gala2k [10]

If she has 10/12 and uses 8/12 then you just subtract.
Since the denominators are the same you just subtract 10-8 and get 2
the denominator is the same for your answers and so it is
2/12

5 0

3 years ago