Answer:
C. 125 + 120x = 180 + 110x
t = $5.5
Step-by-step explanation:
A.125t + 120 = 180t + 110
B. 120t + 110t = 125 + 180
C. 125 + 120t = 180 + 110t
D. 125 - 120t = 180 - 110t
Friday
$125 + 120t
Saturday
110t + 180
equate Friday and Saturday
125 + 120t = 110t + 180
Collect like terms
125 - 180 = 110t - 120t
-55 = -10t
Divide both sides by -10
t = -55 / -10
= 5.5
t = $5.5
Answer:
2.5
Step-by-step explanation:
56(t+1/2)=70 t
56T + 28= 70T
28=70T-56T
28=14
2=T
s=T+ 1/2
S=2+ 1/2
S=2.5 hours

- Simplify :- 1 + - w² + 9w.


Quadratic polynomial can be factored using the transformation
, where
are the solutions of the quadratic equation
.

All equations of the form
can be solved using the quadratic formula:
. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

Square 9.

Multiply -4 times -1.

Add 81 to 4.

Multiply 2 times -1.

Now solve the equation
when ± is plus. Add -9 to
.

Divide -9+
by -2.

Now solve the equation
when ± is minus. Subtract
from -9.

Divide
by -2.

Factor the original expression using
. Substitute
for
and
for
.

<h3>NOTE :-</h3>
Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)
The answer is 5
Explanation:
The 9 by 15 picture is similar to the 3 by x picture, meaning its the same shape but not the same size.
Since we know what the width is for the first picture we have to get the width of the second picture to equal the same width without changing the shape.
To do that you divide BOTH 9 and 15 by 3
And you get 3 and 5.
Hope this help you understand better.
If it has a number before the fraction, it is between that and the next number, if not, it is between 0 and 1. if it is negative, it is between 0 and -1 with the above rules, just if it is only negative