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ivann1987 [24]
2 years ago
10

Line K has a slope of -5. Line J is perpendicular to line K. What is the slope of line K?

Mathematics
1 answer:
attashe74 [19]2 years ago
8 0

If line J is perpendicular of line K, they should cross to make an X. If the slope of line K is -5, Line J would be 5.

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I need help on this what's the answer for it 2/7 + 2/3 =
slava [35]
20/21 is the answer to your problem.

3 0
3 years ago
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Point B has coordinates ​(2​,1​). The​ x-coordinate of point A is negative 1. The distance between point A and point B is 5 unit
Gwar [14]

Answer:

A = (-1,5) or  (-1,-3)

Step-by-step explanation:

A = (-1,y)    B = (2,1)

 

(Distance from A to B) = √[(-1-2)² + (y-1)²] = 5

                                    =√[9 + y² - 2y + 1] = 5

Squaring on both sides

                                     =  y² - 2y + 10 = 25

                                       =y² - 2y -15 = 0

                                      = (y-5)(y+3) = 0

                                         y = 5 or -3

Therefore, A = (-1,5) or  (-1,-3)

6 0
4 years ago
Read 2 more answers
Solve the logarithmic equation. Round the answers to the nearest hundredth. 6+In x=8
ahrayia [7]

Answer:

7.39 ( nearest hundredth )

Step-by-step explanation:

Using the rule of logarithms

log_{b} = n ⇔ x = b^{n}

Note that ln x represents log_{e} x

given 6 + ln x = 8 ( subtract 6 from both sides )

ln x = 2 ⇒ x = e^{2} ≈ 7.39


7 0
3 years ago
What is $200.00 $85.00 $25.34 from least to greatest?
Assoli18 [71]

from Least to Greatest:

$25.34 < $85.00 < $200.00

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B12x-7%3D0%20%5C%5C" id="TexFormula1" title="2x^{2} +12x-7=0 \\" alt="2x^{2}
m_a_m_a [10]

Answer:

-2. 46

- 9.54

Step-by-step explanation:

  • 2x²+12x-7=0
  • 2x²+12x+18= 25
  • 2*(x²+6x+9)=25
  • 2*(x+6)²= 5²
  • x+6= 5√2/2 ⇒ x= 5√2/2 -6 ≈ -2. 46
  • x+6= -5√2/2 ⇒ x= -5√2/2 -6 ≈ - 9.54
4 0
3 years ago
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