Question

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle:

Answer 1

$\huge\boxed{11\ \text{units}}$

To solve this, we need to find the distance between points C and D.

The distance formula is:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values from points $C(x_1, y_1)$ and $D(x_2, y_2)$.

$\sqrt{(-4-(-4))^2+(-5-6)^2}$

Subtract.

$\sqrt{0^2+(-11)^2}$

Evaluate the powers.

$\sqrt{0+121}$

Solve for the final answer.

$\sqrt{121}\\\boxed{11}$