At the end of three days,
% of the original amount of liquid remains in Kyle's container .
<u>Step-by-step explanation:</u>
Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:
Let's suppose initially we have 100% of liquid present so ,
<u>At day 1:</u>
10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
<u>At day 2:</u>
10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
<u>At day 3:</u>
10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
Therefore , At the end of three days,
% of the original amount of liquid remains in Kyle's container .
Answer:
5x-7
Step-by-step explanation:
5 times x (a number) subtract 7
Answer:
The answer is t
Step-by-step explanation:
x works as an exponent so it was pretty easy
3x^2 + 6x - 10 = 0
3(x^2 + 2x) - 10 = 0
3[ (x + 1)^2 - 1 ] - 10 = 0
3(x+1)^2 - 13 = 0
so the vertex is at (-1,-13)
the roots will be same distance from x = -1
that is a distance 1.08 --1 = 2.08
so other root is approximately -1 -2.08 = -3.08
the other intercept is at (-3.08,0)
Because the movement of the minute han of a clock is clockwise ↓, then the angle of rotation will be negative.
1) we calculate the number of minutes from 6:10 to 7:00
number of minutes=7:00-6:10=6:60 - 6:10=50 minutes.
2)
We know that:
60 minutes of a clock have turned -360º
Then:
60 minutes of a clock------------------------- -360º
50 minutes of a clock------------------------- x
x=(50 minutes of a clock * (-360º))/60 minutes of a clock=-300º
Answer: A. -300º