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Marizza181 [45]
2 years ago
12

On a coordinate plane, 2 exponential functions are shown. f (x) decreases from quadrant 2 to quadrant 1 and approaches y = 0. It

crosses the y-axis at (0, 4) and goes through (1, 2). g (x) increases from quadrant 3 into quadrant 4 and approaches y = 0. It crosses the y-axis at (0, negative 4) and goes through (1, negative 2).
Which function represents g(x), a reflection of f(x) = 4(one-half) Superscript x across the x-axis?

g(x) = −4(2)x
g(x) = 4(2)−x
g(x) = −4(one-half) Superscript x
g(x) = 4(one-half) Superscript negative x
Mathematics
1 answer:
aliina [53]2 years ago
3 0

Answer: -4\left(\frac{1}{2} \right)^{x}

Step-by-step explanation:

To reflect the graph of a function across the x-axis,

y=f(x) \longrightarrow y=-f(x)

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A candy manufacturer has 130 pounds of chocolate-covered cherries and 170 pounds of chocolate-covered mints in stock. He decides
Ilia_Sergeevich [38]

Answer:

He should prepare 260 pounds of first mixture and 0 pounds of second mixture

Step-by-step explanation:

Let x be the total quantity ( in pounds ) of cherries and mints in the first mixture and y be the total quantity in second mixture,

Since, first mixture will contain half cherries and half mints by weight,

That is, in first mixture,

Cherries = \frac{x}{2}

Mints = \frac{x}{2},

While, second mixture will contain one-third cherries and two-thirds mints by weight,

That is, in second mixture,

Cherries = \frac{y}{3}

Mints = \frac{2y}{3}

According to the question,

The manufacturer has 130 pounds of chocolate-covered cherries and 170 pounds of chocolate-covered mints in stock,

That is,

\frac{x}{2}+\frac{y}{3} \leq 130

\frac{x}{2}+\frac{2y}{3}\leq 170

Also, pounds can not be negative,

x ≥ 0, y ≥ 0,

Since, the first and second mixture must be sell at the rate of $2.00 per pound and $1.25 per pound respectively,

Hence, the total revenue,

Z = 2.00x + 1.25y

Which is the function that have to maximise,

By plotting the above inequalities,

Vertex of feasible regions are,

(0,255), (180, 120) and (260, 0),

Also, at (260, 0), Z is maximum,

Hence, he should prepare 260 pounds of first mixture and 0 pounds of second mixture in order to maximize his sales revenue.

7 0
3 years ago
Number 14 please thanks
katrin [286]
Your problem is:
$35.00 is what percentage of $437.50?

If you are given a part and the whole, and you want to know what percent the part is of the whole, divide the part by the whole and multiply by 100.

In this case, the whole is $437.50.
The part is $35.00.

35/437.5 * 100 = 8%

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The answer is B because $5.12 was removed from the total she had
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