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Marizza181 [45]
2 years ago
12

On a coordinate plane, 2 exponential functions are shown. f (x) decreases from quadrant 2 to quadrant 1 and approaches y = 0. It

crosses the y-axis at (0, 4) and goes through (1, 2). g (x) increases from quadrant 3 into quadrant 4 and approaches y = 0. It crosses the y-axis at (0, negative 4) and goes through (1, negative 2).
Which function represents g(x), a reflection of f(x) = 4(one-half) Superscript x across the x-axis?

g(x) = −4(2)x
g(x) = 4(2)−x
g(x) = −4(one-half) Superscript x
g(x) = 4(one-half) Superscript negative x
Mathematics
1 answer:
aliina [53]2 years ago
3 0

Answer: -4\left(\frac{1}{2} \right)^{x}

Step-by-step explanation:

To reflect the graph of a function across the x-axis,

y=f(x) \longrightarrow y=-f(x)

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​ On a certain hot​ summer's day, 335 people used the public swimming pool. The daily prices are $1.25 for children and $2.00 fo
spin [16.1K]

Answer:

57

Step-by-step explanation:

Let c represent the number of children ($1.75 each) and a represent the number of adults ( $2.00 each).

We know that there were 340 people total, so c + a = 340. This implies that a = 340 - c

We also know that $1.75 c + $2.00 a = $609.25

By substituting a with 340 -c we have $1.75 c + $2.00 (340 -c) = $609.25

Use the distributive property to obtain $1.75 c + $680 - $2.00 c = $609.25

Subtract $680 from both sides and combine like terms to get - $0.25 c = -

$70.75

Now, divide both sides by -$0.25 to get c = 283, the number of children.

The number of adults is 340 - c or 340 - 283 = 57

4 0
3 years ago
63-28=subtracting by adding up
Tresset [83]

Answer:

35

Step-by-step explanation:

7 0
3 years ago
Find the length of the hypotenuse of a right triangle whose legs are 3 and square root of 2.
madreJ [45]
Square root of 11 because:
sqrt2^2 = 2
3^2 = 9 
so C^2 or the hypotenuse would be the square root of 11 
6 0
3 years ago
What is the quotient. 4x^2+25x+12 divided by x+5
AveGali [126]

 4x2 - 25x + 27

 ——————————————

     x + 5  

3 0
3 years ago
Read 2 more answers
Convert (1, 1) to polar form.<br> A. (2,459<br> B. (1,459)<br> C.(2, 2259)<br> D.(72,459)
timama [110]

Polar form: (r,θ)

Using these formulas:

x²+y²=r²

tan(θ)=y/x

We have the point (1,1) in cartesian coordinates. We need to find r and θ to get it in polar form.

r²=1²+1²

r²=2

r=±√2

tan(θ)=1/1

tan(θ)=1

θ=π/4 radians or 45 degrees

Polar coordinates: (√2,π/4)

Those answer choices look strange. Are you sure these are the right answer choices?

5 0
3 years ago
Read 2 more answers
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