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Sidana [21]
1 year ago
8

How much would it cost to buy a piece of candy for 50 cents plus tax

Mathematics
1 answer:
gtnhenbr [62]1 year ago
5 0

Answer:

it depends on which state your in or in your even in the us usually it is either 6% or 4% some times more or less % so im going to do both

50*0.06=53

50*0.04=52

Hope This Helps!!!

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Each employee receives a 5% raise find the mean median and mode of the data with the race how does this incurs affect the mean m
marshall27 [118]

Answer:

um

Step-by-step explanation:

um sorry bud cant help

7 0
3 years ago
Let the equation of a line be described by Equation A:
umka2103 [35]
10y - 5x = 40   Add 5x to both sides
       10y = 5x + 40   Divide both sides by 10
          y = \frac{1}{2}x + 4

The y-intercept is 4 and the slope of the line is \frac{1}{2}.

You can find these by comparing your equation to the equation y = mx + b, where m is the slope of the line and b is the y-intercept.
4 0
3 years ago
What is the location of point A?
AlladinOne [14]

Answer:

C.-1.6

Step-by-step explanation:

distance: -1 - (-2) = 1

1 ÷ 5 = 1/5

-1 - 1/5 × 3 = -1 3/5 = -1.6

3 0
2 years ago
A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
3 0
3 years ago
The product of a number and -3, increased by 8, is 20
natita [175]

answer:

-4

Step-by-step explanation:

-3x+8= 20

-8 -8

-3x = 12

÷-3. = ÷-3

x = -4

3 0
3 years ago
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