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mixas84 [53]
3 years ago
10

(y-2)^2=-16(x-3) what is it

Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0

(y-2)² = -16(x-3)

y²-4y+4 = -16x+48

y²-4y = -16x + 44

Hope it helped!

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zloy xaker [14]

Given two coordinates point 1 as (-23,-14) and point 2 as(-18,2).

To find the midpoint we would use the formula below;

\text{midpoint(x,y)}=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Where x1=-23, x2=-18, y1=-14, y2=2

We would substitute the values into the midpoint formula.

\begin{gathered} \text{midpoint =(}\frac{-23-18}{2},\frac{-14+2}{2}) \\ =(-\frac{41}{2},-6) \end{gathered}

Therefore, the answer is

\text{midpoint}=(-\frac{41}{2},-6)

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Fantom [35]

Answer:

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Step-by-step explanation:

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