Step-by-step explanation:
1/2x+2−1/6x=1/6x−1−1/6x
1/3x+2=−1
1/3x+2−2=−1−2
1/3x=−3
3*(1/3x)=(3)*(−3)
x=−9 <- ANSWER
Answer:
11.1 years
Step-by-step explanation:
The formula for interest compounding continuously is:

Where A(t) is the amount after the compounding, P is the initial deposit, r is the interest rate in decimal form, and t is the time in years. Filling in what we have looks like this:

We will simplify this first a bit by dividing 2000 by 1150 to get

To get that t out the exponential position it is currently in we have to take the natural log of both sides. Since a natural log has a base of e, taking the natual log of e cancels both of them out. They "undo" each other, for lack of a better way to explain it. That leaves us with
ln(1.739130435)=.05t
Taking the natural log of that decimal on our calculator gives us
.5533852383=.05t
Now divide both sides by .05 to get t = 11.06770477 which rounds to 11.1 years.
Answer:
-2(5)^2
-2(25)
-50
Step-by-step explanation: