Answer:it’s 6
Step-by-step explanation:
First option is correct.
Since we have given that
JKL is a right triangle.
Length of JK = 12
Length of KL = 5
By Pythagoras theorem, we get that

So, cos (L) would be
cos(L)=base/hypotenuse
cos(L)=5/13
Hence, First option is correct.
learn more about Pythagoras theorem and cosine ratios here:
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<h3>
Answer: (x+1)(x+3)</h3>
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Explanation:
Let's assume it factors into (x+a)(x+b)
The goal is to find the two numbers a and b.
FOIL out (x+a)(x+b) to get x^2+(a+b)x+ab
Note how a+b is the middle term and ab is the last term.
In the original expression, 4 is the middle term and 3 is the last term.
So we need to find two numbers that
There are two ways to multiply to 3 and they are
- 1 times 3 = 3
- -1 times -3 = -3
But only the first way has the factors add to 4. So that means a = 1 and b = 3.
Therefore (x+a)(x+b) = (x+1)(x+3)
And x^2+4x+3 = (x+1)(x+3)
Answer:
Step-by-step explanation:
I'll assume that you meant
(8/13) ln 3 = ln h/12
Applying rules of logs, we get:
(8/13) ln 3 = ln h - ln 12
= ln h - ln 3 - ln 4 <= because ln b*c = ln b + ln c
Then (8/13) ln 3 + ln 3 = ln h - ln 4, or
(21/13) ln 3 + ln 4 = ln h
3^(21/13) * 4 = h <= because ln b*c = ln b + ln c