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oee [108]
2 years ago
11

The problem: take two solutions and plug them into the original equation. To check for extraneous solutions.

Mathematics
1 answer:
galben [10]2 years ago
3 0

Answer: х=3.

Step-by-step explanation:

А point is missing here: determining the allowable values of x for this equation.

1. Consider the right side of the equation:

The root expression 2x+3 must be greater than or equal to 0.

2x+3≥0

2x≥-3\ |:2

x≥-1,5.

2. Consider the left side of the equation:

the left side of the equation must be greater than or equal to 0.

x≥0.

We get x≥0.         ⇒

х=3 ∈ х≥0

х=-1 ∉ х≥0.

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Find the surface area of each figure. Round your answer to the nearest tenth if necessary.​
dedylja [7]

Answer:

556

Step-by-step explanation:

Surface area of the cuboid=2*(lb+bh+lh)

Surface area=2*(110+80+88)=556

3 0
3 years ago
What is the acceleration due to gravity of a planet where a mass of 45.0 kg has a weight of
AnnZ [28]

Answer:

Normally, Acceleration due to gravity is

9.8m/s^2\\

or

10m/s^2

Step-by-step explanation:

From the web

These two laws lead to the most useful form of the formula for calculating acceleration due to gravity: g = G*M/R^2, where g is the acceleration due to gravity, G is the universal gravitational constant, M is mass, and R is distance

6 0
4 years ago
Maggie’s brother is 12 years younger that three times her age . The sun of their ages is 44 . How old is Maggie
meriva
I'm not sure if this is right but you can set up an equation and solve to find Maggie's age:

Maggie's brother's age = b
Maggie's age = m

b = 12 - 3m
44 = 12-3m
12-3m = 44
-12 -12
-3m = 32
÷ 3 ÷3
m = 10.67

So this would be Maggie's age

I hope this helped :)
7 0
4 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
Least to greatest 3/2,0.25,-3/4,-1.0
Stels [109]
-1.0, -3/4, 0.25, 3/2


hope this helps :D
7 0
3 years ago
Read 2 more answers
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