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3 years ago

Find the pattern for sequence 5,10,20,40

Mathematics

2 answers:

lord [1]3 years ago

8 0

Answer:

it multiples time 2 every time

Step-by-step explanation:

5 to ten 5times 2

10 to 20 10 time 2

20 to 40. 20 time 2

vlabodo [156]3 years ago

4 0

Answer:

Everything is x2 itself.

Step-by-step explanation:

5x2=10 10x2=20 20x2=40

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A circle with radius 3 has a sector with a central angle of 1/9 pi radians

marissa [1.9K]

Complete question:

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

what is the area of the sector?

Answer:

The area of the sector = $\frac{\pi}{2}$ square units

Step-by-step explanation:

To find the area of the sector of a circle, let's use the formula:

$A = \frac{1}{2} r^2 \theta$

Where, A = area

r = radius = 3

$\theta = \frac{1}{9}\pi$

Substituting values in the formula, we have:

$A = \frac{1}{2}*3^2* \frac{1}{9}\pi$

$A = \frac{1}{2}*9* \frac{1}{9}\pi$

$A = 4.5 * \frac{1}{9}\pi$

$A = \frac{\pi}{2}$

The area of the sector = $\frac{\pi}{2}$ square units

8 0

3 years ago

How do you put the equation 2x+y=2 into slope intercept form

Dahasolnce [82]

Answer:

Step-by-step explanation:

you put the equation in slope and intercept form by making y the subject of the formula

i.e

y = -2x + 2

-2 is the slope and 2 is the intercept

5 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL MARK BTAINLIEST

ivann1987 [24]

Answer:

Range

Step-by-step explanation:

110-76=34

3 0

3 years ago

Find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)

Flauer [41]

Answer:

The coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are $\mathbf{(13,\frac{-9}{2})}$

Step-by-step explanation:

We need to find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)

The midpoint of line segment can be found using formula:

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We have $x_1=14, y_1=-8, x_2=12, y_2=-1$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\Midpoint=(\frac{14+12}{2},\frac{-8-1}{2})\\Midpoint=(\frac{26}{2},\frac{-9}{2})\\Midpoint=(13,\frac{-9}{2})$

So, the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are $\mathbf{(13,\frac{-9}{2})}$

4 0

3 years ago

Marissa says that lines a and d will eventually

dexar [7]

Answer:The last one :)

Step-by-step explanation

8 0

3 years ago

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