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3 years ago

Find the pattern for sequence 5,10,20,40

Mathematics

2 answers:

lord [1]3 years ago

8 0

Answer:

it multiples time 2 every time

Step-by-step explanation:

5 to ten 5times 2

10 to 20 10 time 2

20 to 40. 20 time 2

vlabodo [156]3 years ago

4 0

Answer:

Everything is x2 itself.

Step-by-step explanation:

5x2=10 10x2=20 20x2=40

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Use synthetic division to solve (2x^3+4x^2-35x+15) divided by (x-3) What is the quotient?

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

The only thing you need to watch carefully is the divisor which in this case is x - 3. The divisor, in synthetic division, is the number that will make the binomial go to 0.

x - 3 =0

x = 3

So the divisor is 3.

3 || 2 4 -35 15

6 30 -15

======================

2 10 -5 0

So the quotient is

2x^2 + 10x - 5 with no remainder

7 0

3 years ago

Read 2 more answers

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

Use quadratic formula to find both solutions to the quadratic equation given below . 3x^2-5x-1=0

Rudiy27

Answer:

$x1=\frac{5+\sqrt{37}} {6}$

$x2=\frac{5-\sqrt{37}} {6}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^{2} -5x-1=0$

$a=3\\b=-5\\c=-1$

substitute in the formula

$x=\frac{5(+/-)\sqrt{(-5)^{2}-4(3)(-1)}} {2(3)}$

$x=\frac{5(+/-)\sqrt{37}} {6}$

$x1=\frac{5+\sqrt{37}} {6}$

$x2=\frac{5-\sqrt{37}} {6}$

8 0

3 years ago

Read 2 more answers

You have a fox, a chicken, and a bag of chicken feed, and must take them all to the other side of a river. You have a boat but c

deff fn [24]

Step-by-step explanation:

u take the fox over to the other side, then the chicken feed then the chicken.

6 0

3 years ago

For every 3 tickets you sell, your friend sells 4. You sell a total of 12 tickets. How many does your friend sell?

sweet [91]

the friend sold 16 tickets

4 0

3 years ago