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never [62]
2 years ago
6

A triangle has integer length sides. If two sides of the triangle are 16 and 21, how many possible lengths are there for the thi

rd side
Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
8 0

There are 31 possible lengths for the third side.

Unknown Side +  16 > 21

Unknown Side >  5

16 + 21  > Unknown Side

37 > Unknown Side      

Unknown Side  <  37

So, the possible integer lengths range from

6 -  36  

=   36 - 6 + 1  

= 31 possible lengths

The length of the third side of a triangle has to continually be among (but not equal to) the sum and the distinction among the alternative facets. As an instance, take the example of two, 6, and seven. and consequently, the 0.33 facet length has to be extra than four and less than eight.

The regulation of Cosines to calculate the unknown aspect, then use the Law of Sines to find the smaller of the opposite angles and then use the 3 angles add to 180° to find the final attitude.

Learn more about triangles here brainly.com/question/2437195

#SPJ4

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Solve the equation 1/5(x-2)=1/10(x+6)
Vladimir79 [104]
1/5(x-2)=1/10(x+6)
Distribute and multiply first
(1/5*x) -(1/5*2)=(1/10*x) +(1/10*6)
1/5x-2/5=1/10x+6/10

We do not have the same denominators on both sides. 5 goes into 10 two times so we will multiply everything on the left by 2 to get a common denominator.
2/10x-4/10=1/10x+6/10
Subtract 1/10x from both sides
1/10x-4/10=6/10
Add 4/10 to both sides
1/10x=10/10
1/10x= 1
Multiply both sides by 10/1 (the fraction inverse) to get rid of the fraction.

(10/1)(1/10x) =(1)(10/1)
x= 10

Check work:
1/5(x-2)=1/10(x+6)
Substitute your answer for x
1/5(10-2)=1/10(10+6)
1/5(8)=1/10(16)
8/5=16/10
Simplify 16/10 by dividing by 2
8/5=8/5


Hope this helps!! :)
5 0
3 years ago
Any help on this question?
elena-s [515]

Answer:

50%

Step-by-step explanation:

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Seventh-graders = 18

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3 0
3 years ago
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Csc^ 2 theta- csc^ 2 theta sec^ 2
denis-greek [22]

Answer:

-csc²θ(tan²θ)

Step-by-step explanation:

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8 0
3 years ago
Write a word problem for the following equation: 4x+-3=-11
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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Given f(x)=2x^2-8x+6 and g(x)=3x-1 find f(x) +g(x)
myrzilka [38]

For this case we have the following functions:

f (x) = 2x ^ 2-8x + 6\\g (x) = 3x-1

We must find f (x) + g (x):

We have to:

f (x) + g (x) = 2x ^ 2-8x + 6 + (3x-1)\\f (x) + g (x) = 2x ^ 2-8x + 6 + 3x-1

We add similar terms:

f (x) + g (x) = 2x ^ 2-5x + 5

Answer:

f (x) + g (x) = 2x ^ 2-5x + 5

OPTION C

7 0
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