1/6^3 is also equivalent to 6^-3. It can be reverted back to 1/216. Answers on ed2020 are A. and D.
Answer:
1.49
Step-by-step explanation:
In order to find the slope of the tangent line to a given equation, and in a given point, we need to:
1. Find the first derivative of the given function.
2. Evaluate the first derivative function in the given point.
1. Let's find the first derivative of the given function:
The original function is 
But remeber that the derivative of
is 
so, 
2. Let's evaluate the first derivative function in the given point
The given point is (0.4,1.49) so:



Notice that the calculated slope of the tangent line is equal to the y-coordinate of the given point because f'(x)=f(x). In conclusion, the slope of the tangent line is equal to 1.49.
This is just combining like terms.....
6n2 - 5n2 + 7n2
n2 + 7n2
=8n2
X + 3y = 7
x = -3y + 7
2x + 4y = 8
2(-3y + 7) + 4y = 8
-6y + 14 + 4y = 8
-6y + 4y = 8 - 14
-2y = - 6
y = -6/-2
y = 3
x + 3y = 7
x + 3(3) = 7
x + 9 = 7
x = 7 - 9
x = -2
solution is (-2,3)
Answer:
42/7 is 6 so it would take Mike 6 hours to stich 1 shirt please give brainliest
Step-by-step explanation: