How to solve 45 45 90 triangle given hypotenuse?

1 answer:

4 0

From the Special Triangle Theorem, the hypotenuse is equal to the side lengtht times the Sqrt(2).
So hypotenuse H = xSqrt(2), x=H/Sqrt(2).
Using numbers, if H = 7, then x = 7/Sqrt(2) = 7Sqrt(2)/2 to rationalize it.

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What is an equation of the line that passes through the points (0, -7) and (-8, 3)?

avanturin [10]

Answer (assuming it can be in slope-intercept form):

$y = -\frac{5}{4} x-7$

Step-by-step explanation:

1) First, find the slope of the line by using the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ . Substitute the x and y values of the given points into the formula and solve:

$m = \frac{(3)-(-7)}{(-8)-(0)}\\m = \frac{3+7}{-8-0} \\m = \frac{10}{-8} \\m = -\frac{5}{4}$

So, the slope is $-\frac{5}{4}$ .

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ to write the equation of the line in point-slope form. Substitute real values for the $m$ , $x_1$ , and $y_1$ in the formula.

Since $m$ represents the slope, substitute $-\frac{5}{4}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of one point the line intersects, choose any one of the given points (either one is fine, it will equal the same thing at the end) and substitute its x and y values into the formula as well. (I chose (0, -7), as seen below.) Then, isolate y to put the equation in slope-intercept form and find the following answer:

$y-(-7) = -\frac{5}{4} (x-(0))\\y + 7 = -\frac{5}{4} x\\y = -\frac{5}{4} x-7$

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2 years ago

A line passes through (2,8) and (4,12) which equation best represents the line

Dmitry [639]

Answer:

y=2x+4

Step-by-step explanation:\solving for the slope you get (12-8)/(4-2)=4/2=2

solving for the y intercept you subtract 4 from 8 because 2*2 is 4 and (2,8) is 2 x values away from the y intercept so 8-4=4 so the y intercept is 4

so y=2x+4

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Answer:

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2 years ago