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rodikova [14]
3 years ago
12

What would the answer to this question be? Picture below

Mathematics
2 answers:
diamong [38]3 years ago
5 0

I'm guessing it's 3. -9-3=-12. If it were to be -9- -3, it would be -6.

jekas [21]3 years ago
3 0

Answer:

3

Step-by-step explanation:

-9 - 3 would become -9 + -3, which equals -12

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Can someone help me please ASAP
zmey [24]

Answer:

<h2>140°</h2>

solution,

Let <DEF= x°

<CDE= 2x°

<BAF= 90°

The sum of interior angle of hexagon= 720°

<A + <B + <C + <D + <E +<F = 720°

90 + 145 + 115 + 2x + x + 160 = 720 \\ 510 + 3x = 720 \\3x + 510 = 720 \\ 3x + 510 - 510 = 720 - 510 \\ 3x = 210 \\  \frac{3x}{x}  =  \frac{210}{3}  \\ x = 70 \: degree

Again,

< \: cde = 2x \\  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  = 2 \times 70 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 140 \: degree

Hope this helps...

Good luck on your assignment..

4 0
3 years ago
Which situation can be modeled by the equation 45−2.50x=11.50?
zavuch27 [327]

Answer:

I think either A or D. not sure tho. sry!

4 0
3 years ago
Read 2 more answers
How do I factor out the coefficient of the variable -3/5k-3/10?
Helen [10]

Answer:

make all the numbers have the same denominator, then simply see what multiplies to equal both fractions. your answer should be -3/10(1/5k+1)

Step-by-step explanation:

7 0
3 years ago
Yoko runs10 miles in75 minutes. At the same rate, how many miles would she run in 69 minutes?
Ostrovityanka [42]
She would run 9.2 miles.
3 0
3 years ago
Read 2 more answers
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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